Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.
The ratio of <span>sodium ions to bromide ions in neutral sodium bromide would be 1 is to 1. The molecular formula of sodium bromide would be NaBr where in every ion of Na there is one corresponding ion of bromide present. Hope this helps. Have a nice day.</span>
We can use the atomic model to demonstrate the ways in which scientists
refine and build off each other's findings because of the fact that once
this model was created, it brought with it other models and inventions,
such as the periodic table and other theories about our known universe.
Answer:
Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)
Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻
Explanation:
In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.
In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.
2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)
In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases from -1 to 0.
H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻
Answer:
Explanation:
The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.
In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.
The reaction and the structure of the product is as shown in the attachment.
