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tatyana61 [14]
3 years ago
9

How many coulombs pass through a wire that carries a current of 3.2 A for 5.0 h?

Physics
1 answer:
Stells [14]3 years ago
6 0
I=Q/t 
<span>Q=It </span>
<span>Q=3.2*5*60 </span>
<span>Q=960 </span>
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Answer:

BI/BII = 1

Explanation:

The magnetic field due to a solenoid is given by the following formula:

B = \mu nI\\

where,

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n = No. of turns per unit length

I = current passing through the solenoid

Now for the first solenoid:

B_1 = \mu n_1I_1 \\

For the second solenoid:

B_2 = \mu n_2I_2\\

Dividing both equations:

\frac{B_1}{B_2} = \frac{\mu n_1I_1}{\mu n_2I_2}\\

here, no. of turns and the current passing through each solenoid is same:

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Therefore,

\frac{B_1}{B_2} = \frac{\mu nI}{\mu nI}\\

<u>BI/BII = 1</u>

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3 years ago
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Answer:

Explanation:

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