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Aleks [24]
4 years ago
7

A train accelerates from 23m/s to 190m/s in 54 seconds. What was its acceleration?

Physics
1 answer:
Ierofanga [76]4 years ago
3 0

Answer:

Use the method on the image and solve it.

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Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
When you accelerate in a car and are pushed back into your seat, you are experiencing _______, which is registered by your _____
il63 [147K]

Answer:

E) linear motion; otolith organs 100%

Explanation:

7 0
3 years ago
One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand t
hichkok12 [17]

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

\frac{P1}{T1} = \frac{P2}{T2}

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\

Cross multiplying and making T2 subject of formula we have

T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35

T2= 5.35°C

6 0
3 years ago
Which lens combination is used to treat presbyopia ~ ​
abruzzese [7]

Answer:

People with presbyopia require a convex lens for reading glasses; specialized preparations of convex lenses usually require the services of an optometrist

8 0
2 years ago
The rate at which work is done is also the definition of which of the following?
gregori [183]
B) Power
Because Power= Work/time
7 0
3 years ago
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