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4 years ago

8

Why do lunar and solar eclipses not happen every month?

2 answers:

inessss [21]4 years ago

7 0

Answer:

The moon’s axis does not always align with Earth’s shadow.

Explanation:

The lunar eclipse happens when the Earth comes between the moon and the Sun, blocking the light falling on the moon. It occurs on a full moon. On the other hand, a solar eclipse occurs when the moon comes between the Earth and the Sun, blocking the sunlight falling on Earth. It occurs on new moon day. For each to occur, the three bodies must be aligned in straight line. As the orbital plane of the moon is not exactly aligned to that of the Earth, the eclipses do not occur every month.

Tamiku [17]4 years ago

4 0

Answer:

pretty sure it is d..

Explanation:

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At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee

lawyer [7]

Thrust is a reaction force described quantitatively by Newton's third law. When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction on that system. Mathematically can be written as,

$T = v\frac{dm}{dt}$

Here,

v = speed of the exhaust gases measured relative to the rocket.

$\frac{dm}{dt}$ = Rate of change of mass with respect to time

Our values are given as,

$v = 1500m/s$

$\frac{dm}{dt} = 100kg/s$

Replacing we have that

$T = 1500*100$

$\therefore T = 1.5*10^5N$

7 0

3 years ago

What is the impulse that a car with mass of 5kg experiences when its velocity changes from -9m/s to 25m/s?

Amiraneli [1.4K]

Answer:

170 kg m/s

Explanation:

Impulse = change in momentum

J = m Δv

J = (5 kg) (25 m/s − (-9 m/s))

J = 170 kg m/s

4 0

3 years ago

Read 2 more answers

7. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The oncoming water stream has

NNADVOKAT [17]

Answer:

The magnitude of the average force exerted on the water by the blade is 960 N.

Explanation:

Given that,

The mass of water per second that strikes the blade is, $\dfrac{m}{t}=30\ kg/s$

Initial speed of the oncoming stream, u = 16 m/s

Final speed of the outgoing water stream, v = -16 m/s

We need to find the magnitude of the average force exerted on the water by the blade. It can be calculated using second law of motion as :

$F=\dfrac{\Delta P}{\Delta t}$

$F=\dfrac{m(v-u)}{\Delta t}$

$F=30\ kg/s\times (-16-16)\ m/s$

F = -960 N

So, the magnitude of the average force exerted on the water by the blade is 960 N. Hence, this is the required solution.

6 0

4 years ago

For a flourish at the end of her act, a juggler tosses a single ball high in the air. She catches the ball 3.2 s later at the sa

MAXImum [283]

Answer:

15.68 m/s

Explanation:

Given that,

She catches the ball 3.2 s later at the same height from which it was thrown.

When it reaches the maximum height, its height is equal to 0.

It will move under the action of gravity.

$t=\dfrac{2u}{g}$

2 here comes for the time of ascent and descent.

So,

$u=\dfrac{tg}{2}\\\\u=\dfrac{3.2\times 9.8}{2}\\\\u=15.68\ m/s$

So, the initial upward speed of the ball is 15.68 m/s.

6 0

3 years ago

You lay a mirror flat on the floor with one edge against a wall and aim a laser at the mirror. The ray reflects from the mirror

RideAnS [48]

Answer:

About 32.6°

Explanation:

The tangent of the desired angle is the ratio of distance from the wall to height up the wall:

tan(angle of incidence) = (22.7 cm)/(35.5 cm) ≈ 0.63944

angle of incidence = arctan(0.63944) ≈ 32.6°

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The angle of incidence is measured from the normal to the mirror.

5 0

3 years ago

Read 2 more answers