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ahrayia [7]
3 years ago
6

3/10

Physics
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

4,800?

First I subtracted 8 from 24 because there are 24 hours in a day ad she spends 8 of those hours sleeping. I then took the answer which was 16, and multiplied that by 60 to find out how many minutes were in 16 hours and I got 960. I then multiplied 960 by 5 because she winks 5 times each minute. This left me with the answer 4,800.

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How is the process of cooling from a water vapor to ice different to heating ice to water vapor?
garik1379 [7]

In ice the molecules are stuck rigidly together and vibrate in place. In liquid water they slide and bump past one another. In water vapor they are much farther apart and they bounce around freely.

<em>pls mark brainliest</em>

8 0
3 years ago
Find the velocity of a runner who has a mass of 75 kg and 3,700 Joules of energy.
Gelneren [198K]

Answer:

125 joules

Explanation:

7 0
3 years ago
What is the order of magnitude of the gravitational force between two 1.0 kilogram charges that are positioned 1.0 meter apart?
stiks02 [169]

The answer is  -11

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6 0
3 years ago
Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t
Allisa [31]
The minimum frequency is 
f_1 = 550 kHz = 5.50 \cdot 10^5 Hz
while the maximum frequency is
f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz
Using the relationship between frequency f of a wave, wavelength \lambda and the speed of the wave v, we can find what wavelength these frequencies correspond to:
\lambda_1 =  \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m
\lambda_2 =  \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m

So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

5 0
3 years ago
5. How many kilowatt-hours of energy would be used by a 40 W bulb that runs for 10 hours every
Nady [450]

Answer:

E = 0.4 kWh

Explanation:

Given that,

The power of a bulb, P = 40 W

Time, t = 10 hours

We need to find the energy used by the bulb. Let it is equal to E. So,

E=P\times t\\\\E=40\times 10\\\\E=400\ W-h\\\\or\\\\E=0.4\ kWh

So, 0.4 kWh of energy would be needed.

6 0
3 years ago
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