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ahrayia [7]
2 years ago
6

3/10

Physics
1 answer:
lyudmila [28]2 years ago
7 0

Answer:

4,800?

First I subtracted 8 from 24 because there are 24 hours in a day ad she spends 8 of those hours sleeping. I then took the answer which was 16, and multiplied that by 60 to find out how many minutes were in 16 hours and I got 960. I then multiplied 960 by 5 because she winks 5 times each minute. This left me with the answer 4,800.

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What type of friction prevents a pile of rocks from falling apart?
BlackZzzverrR [31]
A because it some type of friction
6 0
2 years ago
What distance does electromagnetic radiation travel in 55.0 μs ?
Komok [63]
Electromagnetic radiation is an energy that is known as light. so electromagnetic radiation will have the same speed as the speed of light which is 3 x 10^8 m/s. so the distance it travel at 55 x 10^-6 s is:
D = ( 3 x 10^8 m/s ) (  55 x 10^-6 s )
D = 16500 m
4 0
3 years ago
A seesaw pivots as shown in below. What is the net torque about the pivot point?
rodikova [14]

Answer:

2.3 Nm clockwise

Explanation:

Take counterclockwise to be positive and clockwise to be negative.

∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)

∑τ = 7.5 Nm − 9.8 Nm

∑τ = -2.3 Nm

The net torque is 2.3 Nm clockwise.

7 0
3 years ago
Two long, parallel, current-carrying wires lie in an xy-plane. The first wire lies on the line y = 0.300 m and carries a current
Marrrta [24]

Answer:

Explanation:

Since the wires attract each other , the direction of current will be same in both the wires .

Let I be current in wire which is along x - axis

force of attraction per unit length between the two current carrying wire is given by

\frac{\mu_0}{4\pi}  x \frac{2 I_1\times I_2}{d}

where I₁ and I₂ are currents in the wires and d is distance between the two

Putting the given values

285 x 10⁻⁶ = 10⁻⁷ x \frac{2\times25.5\times I_2}{.3}

I₂ = 16.76 A

Current in the wire along x axis is 16.76 A

To find point where magnetic field is zero due the these wires

The point will lie between the two wires  as current is in the same direction.

Let at y = y , the neutral point lies

k 2 x  \frac{16.76}{y} = k 2 x \frac{25.5}{.3-y}

25.5y = 16.76 x .3 - 16.76y

42.26 y = 5.028

y = .119

= .12 m

3 0
3 years ago
If I connect an inductor (L) to a capacitor (C), I will get an LC oscillator circuit with some natural frequency omega. If I wer
mart [117]

The new natural frequency would be ω/2.

we know that,

f = \frac{1}{2 pi \sqrt{LC} } = ω.       -> equation 1

now, when capacitance is quadrupled,

f' = \frac{1}{2 pi \sqrt{L ( 4C )} }

f' = \frac{1}{2 pi (2)\sqrt{LC} }.           -> equation 2

substituting value of equation 1 in equation 2 , we get,

f' = \frac{w}{2}

Hence, the new natural frequency of the circuit is ω/2.

what do you mean by frequency ?

The resonant frequency for a particular circuit is the frequency at which this equality stands true. Where L is the inductance in henries and C is the capacitance in farads, this is the  LC circuit's resonant frequency.

Learn more about frequency here:-

brainly.com/question/12530980

#SPJ4

8 0
2 years ago
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