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DENIUS [597]
3 years ago
8

Olivia is on a swing at the playground at which point is her kinetic energy increasing and her potential energy decreasing

Physics
2 answers:
Nimfa-mama [501]3 years ago
7 0
Whenever an object is falling, its potential energy
is decreasing and its kinetic energy is increasing.

Olivia's potential energy is decreasing and her kinetic energy
is increasing as she moves toward the right side of the picture,
all the way from W, through X, to the bottom of the arc.
eduard3 years ago
7 0

Answer: W

Explanation:

Kinetic energy is due to motion of a body.

K.E. = 0.5 m v²

Potential energy is due to position of the body. In this case it is determined by the height.

P.E. = m g h

At the highest point potential energy is maximum. As the Olivia swings down, potential energy converts to kinetic energy. Thus, at point W, potential energy is decreasing and kinetic energy is increasing. Kinetic energy would be maximum at lowest point.

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1.what is gravity?(in your own words)
olga_2 [115]

Answer:

1.Gravity is an invisible force that pulls objects toward each other

2.The suns gravity pulls the planet towards the sun which changes the straight line of direction into a curve

That keeps the planet moving in an orbit around the sun

hope it helped:)

8 0
3 years ago
Dish-shaped reflectors are used to steer microwaves in order to establish communications links between nearby buildings. Those r
Ad libitum [116K]

A "screen" or even just a set of parallel bars are highly reflective to electromagnetic waves as long as the open spaces are small compared to the wavelengths.

"Grid" dishes work fine ... with less weight and less wind resistance ... for frequencies below about 3 GHz. (Wavelengths of at least 10 cm.)

(I even worked on a microwave system in South America where huge grid dishes were used on a 90-mile link.)

5 0
3 years ago
What is the maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee?
Bad White [126]

The maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee 119.28N.

Given,

m=76kg, μ=0.16, g=9.81 m/s^{2}

frictional force = mμg= 76*0.16*9.81= 119.28 N

<h3>Frictional force</h3>

An opposing force to the relative motion of two bodies in contact is known as frictional force. Always acting in the opposite direction from the direction of motion, frictional force is applied to a moving body. Because it resists motion, it aids in lowering the moving object's speed. The force is one of touch. Four broad categories can be made for the force of friction depending on the sort of motion that occurs between the two objects. Static friction is the force of friction between an object and the surface it is put on.

What is the maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee?

Learn more about frictional force here:

brainly.com/question/13707283

#SPJ4

4 0
2 years ago
Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is &lt; 2, 0, 3 &gt; m and its speed is
Paraphin [41]

Answer:

The workdone by Jack is  W_{jack} = -1050J

The workdone by Jill is  W_{Jill} = 0J

The final velocity is  v = 1.36 m/s

Explanation:

From the question we are given that

          The mass of the boat is m_b = 3300kg

          The initial position of the boat is   P_i  = (2 \r  i  + 0 \r j + 3\r k)m

           The Final position of the boat is  P_f = (4\r i + 0 \r j + 2\r k )\ m

           The Force exerted by Jack \r F = (-420\r i + 0 \r j + 210\r k) \ N

             The Force exerted by Jill  \r F_{Jill} =(180 \r i + 0\r j + 360\r k)

Now to obtain the displacement made we are to subtract the final position from the initial position

                                 \r P = P_f - P_i

                                    = (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k  )

                                     = (2\r i + 0\r j -\r k )m

Now that we have obtained the displacement we can obtain the Workdone

  which is mathematically represented as

                                                   W =\r  F * \r P

 The amount of workdone by jack would be

                                               W_{jack} =\r  F * \r P

                                                 = [(-420\r i +0\r j +210\r k)(2\r  i + 0\r j - \r k)]

                                                 = (-420) (2) + (210)(-1)

                                                = -840 - 210

                                               =-1050J

  The amount of workdone by Jill would be

                                                 W_{Jill} =\r  F * \r P

                                                        = [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]

                                                       = (180 )(2) +(360)(-1)

                                                       =0J

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

              W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]

             -1050  = 0.5*3300 [*v^2- (1.1)^2]

            -1050 = 1650 [v^2 -1.21]

               0.6363 = v^2 -1.21

                   v^2 = 0.6363+1.21

                    v^2 =1.846

                    v = 1.36\ m/s

                   

6 0
4 years ago
A runner is training and runs past meter mark 65 and starts a stopwatch. After the runner passes meter mark 15 the stopwatch sto
denis-greek [22]

Answer:

6.25 m/s

Explanation:

Given parameters

Initial mark = 65

Final mark  = 15

time taken = 8s

Unknown:

Velocity of the runner  = ?

Solution:

Velocity is the displacement divided by time;

        Velocity  = \frac{displacement}{time}  

Displacement  = Initial mark - final mark  = 65 - 15 = 50m

Now, insert the parameters and solve;

       Velocity  = \frac{50}{8}   = 6.25m/s

7 0
3 years ago
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