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3 years ago

14

On Monday 1/9 of the enrolled students in a school were absent. There were 4,512 students present how many students are enrolled

at the school in total ?

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:6599 i think

Step-by-step explanation:

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The length of a rectangle is 16 inches, and it's area is (32x + 48) square inches. Factor the expression for the area. Write an

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16(32x + 48) 32x * 16+=w

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3 years ago

Passes through (-1,4) and has a slope of 4

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Answer:

y-4=4(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

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3 years ago

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What is the period of the graph of y = 5cos(6x – 1) + 3?<br> O A.

evablogger [386]

Step-by-step explanation:

The coefficent of the x variable is b.

The formula for the period is

$\frac{2\pi}{ |b| }$

Here, b is 6 so we have

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So the period is pi/3, or 60 degrees

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2 years ago

A. 6<br> B. ⟌50<br> C. ⟌34<br> D. 4<br><br> Which one?

AfilCa [17]

Answer:

C

Step-by-step explanation:

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3 years ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago