CP=12, CM=20. CP is the altitude of the triangle. ACP is a right triangle, so you can solve for CP using Pythagorean's theorem. CP=\sqrt(AC^2-CP^2)=\sqrt(15^2-9^2)=12. AM=AP+PM=9+16=25. Triangle ACM is another right triangle, and CM=\sqrt(AM^2-AC^2)=\sqrt(25^2-15^2)=20.
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//Hope this helps. Look the image for better understanding.
Answer:
m∠J = 45° , m∠I = 45° and m∠M = 90°
And the ΔJIM is an isosceles right angled triangle.
Step-by-step explanation:
(a). In ΔJIM,
∠J = 2x + 15,
∠I = 5x - 30, and
∠M = 6x
Now, using angle sum property of a triangle that sum of all the angles in a triangle is 180°
⇒ ∠J + ∠I + ∠M = 180°
⇒ 2x + 15 + 5x - 30 + 6x = 180°
⇒ 13x -15 = 180°
⇒ 13x = 195
⇒ x = 15
Therefore, m∠J = 45° , ∠I = 45° and m ∠M = 90°
(b). Now, ΔJIM is a right angled triangle right angled at M.
Also, ∠J = ∠I = 45°
So, JM = IM ( because in a triangle sides opposite to equal angles are equal)
So, ΔJIM is an isosceles triangle because its two sides are equal.
Hence, ΔJIM is a right angled isosceles triangle right angled at M.
you miss something, maybe log is lg.
Write it as 0.35. Hope it helps.
