Answer:
A: a(t)
B: v(t)
C: s(t)
Step-by-step explanation:
One graph is position, s(t).
Another is velocity, v(t) = ds/dt (slope of the tangent line of the position curve).
The third is acceleration, a(t) = dv/dt (slope of the tangent line of the velocity curve).
If graph A is s(t), then velocity v(t) would always be positive. No graph fits, so A is not s(t).
If graph B is s(t), then velocity v(t) would start negative then become positive, like graph A does. If graph A is v(t), then acceleration a(t) would always be positive. No graph fits, so A is not v(t), which means B is not s(t).
If graph C is s(t), then velocity v(t) would always be negative, like graph B. If graph B is v(t), then acceleration a(t) starts negative then becomes positive, like graph A does.
Therefore:
A: a(t)
B: v(t)
C: s(t)
