Answer:
The distance from B to B' is 5 units
Step-by-step explanation:
The complete question is
Polygon ABCD is translated to create polygon A'B'C'D'. Point A is located at (1,5) and point A' is located at (-2,1). What is the distance from B to B'?
we know that
In a translation the figure maintains its dimensions and internal angles
so
AA'=BB'=CC'=DD'
The distance BB' is the same that the distance AA'
<em>Find the distance AA'</em>
the formula to calculate the distance between two points is equal to
we have
A(1,5),A'(-2,1)
substitute in the formula
therefore
The distance from B to B' is 5 units
<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
Answer:
40%
Step-by-step explanation:
Subtract 1,400 by 1,000 then divide by 1,000
120 degrees the sum of all is 720