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4 years ago

Define diffusion.........................................

Chemistry

1 answer:

Iteru [2.4K]4 years ago

4 0

Answer:

the gradual movement of particles from a place of high concentration to low concentration

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2 Na + Cl2 --> 2 NaCl What is the mole ratio of sodium to sodium chloride?

Irina18 [472]

Answer: The mole ratio of sodium to sodium chloride 2:2.

Explanation:

As the given reaction equation is as follows.

$2Na + Cl_{2} \rightarrow 2NaCl$

Here, 2 moles of sodium reacts with 1 mole of $Cl_{2}$ and leads to the formation of 2 moles of NaCl.

This means that 2 moles of sodium gives 2 moles of NaCl on reaction with chlorine.

Hence, the ratio of moles of sodium to sodium chloride is 2:2.

Thus, we can conclude that the mole ratio of sodium to sodium chloride 2:2.

6 0

3 years ago

What is the PTP for 11/4? serving size portion size big mac size

vagabundo [1.1K]

The answer is Big Mac size

4 0

3 years ago

Temperature in degrees Fahrenheit can be converted to Celsius by first subtracting 32, then dividing by 1.8. What is the Celsius

kap26 [50]

Answer:

31.1°C

Explanation:

Given parameters:

Temperature = 88°F

The formula of the to convert is:

T°F = T°C - 32 / 1.8 = $\frac{TC - 32}{1.8}$

Now input the parameters and solve;

T°F = $\frac{ 88 -32}{1.8}$

T°F = 31.1°C

7 0

3 years ago

Read 2 more answers

Consider the balanced equation.

vaieri [72.5K]

The balanced chemical reaction is:

N2 + 3H2 = 2NH3

We are given the amount of H2 being reacted. This will be our starting point.

26.3 g H2 (1 mol H2 / 2.02 g H2) 2 mol O2/3 mol H2) ( 17.04 g NH3 / 1mol NH3) = 147.90 g O2

Percent yield = actual yield / theoretical yield x 100

Percent yield = 79.0 g / 147.90 g x 100

Percent yield = 53.4%

8 0

3 years ago

Read 2 more answers

At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure

Llana [10]

Answer: The value of $K_p$ for the given chemical reaction is 0.1415

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as $K_p$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_p$ is written as:

$K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}$

For the given chemical equation:

$H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)$

The expression for $K_p$ for the following equation is:

$K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}$

We are given:

$p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm$

Putting values in above equation, we get:

$K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415$

The value of $K_p$ for the given chemical reaction is 0.1415

5 0

3 years ago