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r-ruslan [8.4K]
4 years ago
14

Define diffusion.........................................

Chemistry
1 answer:
Iteru [2.4K]4 years ago
4 0

Answer:

the gradual movement of particles from a place of high concentration to low concentration

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Free_Kalibri [48]

Answer:

50cm

Explanation:

3 0
4 years ago
Read 2 more answers
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
What is the hydronium ion concentration of a solution whose pH is 7.30
Assoli18 [71]
[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

hope this helps!
6 0
3 years ago
A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t
gladu [14]

<u>Solution</u> : Emperical Formula =  CH_{3}

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

            20.0g Hydrogen

First convert the given masses into moles.

80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}

20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

\frac{6.66}{6.66}\text{mole of C}= 1

\frac{20.0}{6.66}\text{mole of C}= 3

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula =  CH_{3}

3 0
4 years ago
This picture shows students working in a
Lilit [14]

Answer:

yes it is true they apply necessary safety measures

8 0
3 years ago
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