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Moles of Carbon dioxide : 0.75
<h3>Further explanation</h3>
Given
23 g C₃H₈O₃
Required
Moles of Carbon dioxide
Solution
Reaction
2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O
mol C₃H₈O₃ :
= mass : MW
= 23 g : 92,09382 g/mol
= 0.24975
From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :
= 3/1 x mol C₃H₈O₃
= 3/1 x 0.24975
= 0.74925≈0.750 mol
A.meter is the is the answer to the problem you and and if you need to know why then type back
Answer:
1.85 g of hydrogen gas will form!
Explanation:
1. Write the balanced equation.
Zn
+
2HCl
→
ZnCl
2
+
H
2
2. Calculate the moles of
Zn
.
Moles of Zn
=
30.0
g Zn
×
1 mol Zn
65.38
g Zn
=
0.4589 mol Zn
3. Calculate the moles of
H
2
.
Moles of H
2
=
0.4589
mol Zn
×
2 mol H
2
1
mol Zn
=
0.9177 mol H
2
4. Calculate the mass of
H
2
.
Mass of H
2
=
0.9177
mol H
2
×
2.016 g H
2
1
mol H
2
=
1.85 g H
2
