If a gas occupies 2.3 liters at a pressure of 1.9 atm, what will be its volume at a pressure of 3.8 atm?
2 answers:
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<u>Answer:</u> The mass of potassium superoxide required is 142.2 grams
<u>Explanation:</u>
The chemical equation for the reaction of potassium superoxide with water follows:
Number of moles of potassium superoxide reacted = 2 moles for given amount of heat released
To calculate the mass for given number of moles, we use the equation:
Molar mass of potassium superoxide = 71.1 g/mol
Moles of potassium superoxide = 2 moles
Putting values in above equation, we get:
Hence, the mass of potassium superoxide required is 142.2 grams