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igomit [66]
3 years ago
11

A student increases the temperature of a 200 cm3 balloon from 33degrees C to 47 degrease C. What will the new volume of the ball

on be?
Chemistry
1 answer:
sveta [45]3 years ago
7 0
The answer is 209.15cm3

The volume is directly related to the temperature of a gas. You can solve this question using Charles' law, but remember to convert the temperature from Celcius to Kelvin.

V1/T1= V2/T2
<span>200 cm3/ (33+273K)= V2/(47+273K)
V2= 200cm3 * 320/306= 209.15cm3</span>
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Answer:

Yes

Explanation:

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What are the potential problems for nearby water sources when using nuclear energy? Check all that apply.
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5 0
3 years ago
Read 2 more answers
If u can help answer these questions i’ll mark you brainliest, pls it’s due tomorrow
AveGali [126]

Explanation:

First Question:

The equation is given as;

2KClO3  --> 2KCl + 3O2

2 mol of KClO3  produces 2 mol of KCl

Converting 7.6 g of KCl to mol;

Number of moles = Mass / Molar mass = 7.6 / 74.5513  = 0.1019

2 mol = 2 mol

x mol = 0.1019

solving for x;

x = 0.1019 mol of KClO3

converting to mass;

Mass = Number of mol * Molar mass = 0.1019 * 122.55 = 12.48

Correct option = B. 12.5 g

Second Question

The equation is given as;

1N2 + 3H2 --> 2NH3

3 mol of H2  produces 2 mol of NH3

Converting 34.06g of NH3 to mol;

Number of moles = Mass / Molar mass = 34.06 / 17.031 = 2 mol

3 mol = 2 mol

x mol = 2 mol

Solving for x;

x = 6 / 2 = 3 mol of H2

Converting 3 mol H2 to g;

Mass = Number of moles * Molar mass = 3 * 2.016 = 6.048g

Correct option: B. 6.05g

3 0
3 years ago
Which type of molecule is shown below?
worty [1.4K]
We will need to see what the picture looks like post the picture of the molecule
8 0
3 years ago
Calculate the number of grams of 02, produced when 43 grams of potassium chlorate decomposes.
Dafna11 [192]

Mass O2 = = 16.832 g

<h3>Further explanation</h3>

Given

43 grams of potassium chlorate

Required

Mass of O2

Solution

Reaction

2KClO3 ⇒3O2 + 2KCl

Mol KClO3 :

= mass : MW

= 43 g : 122,55 g/mol

= 0.3509

From the equation, mol O2 :

= 3/2 x moles KClO3

= 3/2 x 0.3509

= 0.526

Mass O2 :

= 0.526 x 32 g/mol

= 16.832 g

4 0
3 years ago
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