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Gre4nikov [31]
3 years ago
9

What role do wolves play in the tundra?

Chemistry
2 answers:
nydimaria [60]3 years ago
6 0
Predator? Not sure if that’s what your looking for.
Orlov [11]3 years ago
4 0

Answer:

predator

Explanation:

Wolves, arctic foxes, and snowy owls are predators in the tundra.

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The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mo
boyakko [2]

Answer:

C₂H₂ + 3H₂ ⟶ 2CH₄  

Explanation:

The initial concentrations are:

[CH₄] = 6.30 ÷ 6.00 =   1.05  mol·L⁻¹

[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹

   [H₂] = 11.15 ÷  6.00 =  1.858 mol·L⁻¹

                2CH₄ ⇌ C₂H₂ + 3H₂

I/mol·L⁻¹:    1.05     0.700   1.858

Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07

Q > K

That means we have too many products.

The reaction will go to the left to get rid of the excess products.

C₂H₂ + 3H₂ ⟶ 2CH₄

8 0
4 years ago
Is condensation of ethanol a physical change or a chemical change
tigry1 [53]

Answer: Physical change

Explanation: Condensation is the phase change of a gas to the liquid state. There is no formation of new products so it does not undergoes chemical change. Any phase change is considered a physical change.

7 0
4 years ago
For every 5.00 mL of milk of magnesia there are 400. mg of magnesium hydroxide. How many mL of milk of magnesia do we need to ne
trasher [3.6K]
Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O 

(0.0500 L) x (0.500 mol/L HCl) x (1 mol Mg(OH)2 / 2 mol HCl) x (58.3197 g Mg(OH)2/mol) = 0.729 g = 729 mg Mg(OH)2 

<span>(729 mg Mg(OH)2) x (5.00 mL / 400 mg) = 9.11 mL milk of magnesia</span>
7 0
3 years ago
Read 2 more answers
Which of the following is true about lava and magma? A Lava and magma are both types of molten rock. B Magma uses waves to break
Gre4nikov [31]

Answer:

a

Explanation:

magma is lava and lava is magma

4 0
3 years ago
how many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?
dezoksy [38]
Data:

P (pressure) = 2.3 atm
V (volume) = 120 L
T (temperature) = 340 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula: 

p*V = n*R*T

Solving:
p*V = n*R*T
2.3*120 = n*0.082*340
276 = 27.88n
27.88n = 276
n = \frac{276}{27.88}
n = 9.89956...\to \boxed{\boxed{n\approx 9.90\:mols}}\end{array}}\qquad\quad\checkmark


7 0
4 years ago
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