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mixer [17]
3 years ago
15

Choose all that apply. Nitrogen has an atomic number of 7. Its atomic mass is 14. Nitrogen has

Chemistry
1 answer:
Goshia [24]3 years ago
6 0
The  atomic  number  of  calculated as  number  of  protons  +  number  of  neutrons. The  number  of  protons  are  the  same  as  atomic  number.  This  implies  that  Nitrogen  has  seven  protons.  To  get  the  the  number  of  neutron  we minus  atomic  mass  from  number  of  protons
     that  is  14-7=7  neutrons
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The combination of oxygen with other substances to produce new chemical products is called
Flauer [41]

Answer:

                 The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.

Explanation:

                     Oxidation reactions are defined as,

In terms of Inorganic chemistry:

                 (i) <u>Removal of Electrons: </u>

                            Example:  Mg  →  Mg²⁺  +  2 e⁻

                (ii) <u>Addition of Oxygen:</u>

                            Example:  2 Mg  + O₂  →  2 MgO

In terms of Organic chemistry:

                (i) <u>Addition of Electrons: </u>

                            Example:  Cl₂  +  2 e⁻   →   2 Cl⁻

                (ii) <u>Addition of Hydrogen:</u>

                            Example:  H₂CCH₂  +  H₂    →   H₃CCH₃

4 0
3 years ago
How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

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3 years ago
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posledela

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I hope im  right! !!

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