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gregori [183]
3 years ago
14

Which of these is a base ? a.vinegar b.NaOH c.HNO3 d.HCI

Chemistry
2 answers:
aksik [14]3 years ago
8 0

A - Vinegar - Acid

B - NaOH- Base

C - HCL - Acid

D - HNO3 - Acid

NaOH is a base because when it is dissolved in water it dissociates into Na+ and OH- ions. When it had OH- ( hydroxyl ion ) ions, it automaticly is a base; thus, NaOH must be a base.

Hope this helps! :)

sergey [27]3 years ago
6 0

Answer:

B. NaOH

Explanation:

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More strong base is added until the equivalence point is reached. what is the ph of this solution at the equivalence point if th
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A more strong base is added until the equivalence point is reached. The ph of this solution at the equivalence point if the total volume is 57. 0 mill is 9.8

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

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1 year ago
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7 0
3 years ago
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Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has
bija089 [108]
<h2>Answer:</h2>

Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic  \: mass }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 72 \times84.9 + 28 \times 87  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 6112.8 + 2436  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 8548.8  }{100} \\

\footnotesize \longrightarrow \:  \bf Average \:  atomic  \: mass =  85.488 \: amu  \\

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zaharov [31]
 i think..
potassium hydroxide..
4 0
3 years ago
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