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patriot [66]
4 years ago
13

Is V directly proportional to I (From V=IR)??

Physics
2 answers:
11111nata11111 [884]4 years ago
4 0

First of all, I is proportional V according to the Ohm's Law. R is merely a constant you need to obtain an equation. However, it is true that R changes with temperature and pressure, therefore Ohm's Law is only applicable in an invariable environment. Also this constant R is different for different materials.

So, do not get confused.

Ohm's law is not a universal law, please remember that as well. Some materials do not follow it and we call them non-ohmic conductors. I hope I helped! ^-^

maksim [4K]4 years ago
4 0
This question relates to how electricity is transmitted on various NATIONAL GRIDS. AC is used, partly because it can be transformed using a transformer. To get the electricity or maybe I should say the electrical POWER from A 1000 miles to B, if it were transitted at 250 V then the actual CURRENT needed in the line would be very high. That would cause problems in the cables, one of which would be heating. So, the voltage is stepped up to say 2500 V and v possibly more. Then the current going down the transmission lines is less, but the power transmitted is the same. At the B station, the AC is transformed from the 2500V transmission voltage back down to the commercial/domestic voltage of 250V. Then the current required can be drawn, 'cos the power has "got there".
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Use the work energy theorem to solve each of these problems and neglect air resistance in all cases. a) A branch falls from the
Sav [38]

Answer:

a)43.8 m/s

b)103.54 m/s

Explanation:

Work energy theorem

ΔE_{k}= ΔE_{g}

E_{k2} - E_{k1}=-(E_{g2} - E_{g1})\\\\ \frac{1}{2} mv^{2}_{2}- \frac{1}{2} mv^{2}_{1}+ mgh_{2} - mgh_{1} = 0

a) In this part v1=0 and h2=0

\frac{1}{2} mv^{2}_{2}- \frac{1}{2} mv^{2}_{1}+ mgh_{2}- mgh_{1} = 0\\\\\\\\\v_{2} =\sqrt{2gh_{1}} = \sqrt{2*9.8*98} =43.8 m/s=0

b) in this part v2=0, h1= 0, and h2= 545m

\frac{1}{2} v^{2}_{1}= gh_{2} \\v_{1} =\sqrt{2gh_{2}}=103.54m/s

5 0
3 years ago
If the force acting on a body of mass 4 kg is doubled. by how much will the acceleration change?
mr Goodwill [35]

Answer:

The acceleration will also double

Explanation:

F = m*a

a = F/m

plugging in sample numbers to prove

a= 100/4   = 25

a = 200/4 = 50

3 0
3 years ago
What a scientist often conducts a controlled experiment,which is?
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8 the height variations

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7 0
3 years ago
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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init
Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= \frac{3*lamda}{2}

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

δ= \sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}

δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

δ= \sqrt{4900+1849}-\sqrt{4900+529}

δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

δ= 8.47

8.47 = \frac{3*lamda}{2}

λ = \frac{8.47*2}{3}

λ = 5.65m

3 0
4 years ago
Which statement comparing examples of renewable and nonrenewable resources is true?
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I believe the answer is A
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4 years ago
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