Explanation:
It is given that,
The ramp is tilted upwards at 25 degrees and Paul is pulling a large crate up the ramp with a rope that angles 10° above the ramp.
Total angle with respect to ramp is 35 degrees.
If Paul pulls with a force of 550 N.
The horizontal component of the force is given by :
The vertical component of the force is given by :
Hence, this is the required solution.
Answer:
The coefficient of static friction is 0.29
Explanation:
Given that,
Radius of the merry-go-round, r = 4.4 m
The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.
We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.
v is the speed of cat,
So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.
Explanation:
Given that,
Current, I = 0.015 A
Voltage, V = 240 volts
We need to find the resistance. Using Ohm's law we can find it as follows :
So, When a current of 0.015 A passes through human body at 240 volts p.d it causes 16000 ohms of resistance.