No cluuuueee :/ sowwwwyyy but good luck
Answer:
Approximately
.
Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.
Explanation:
Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant
near the surface of the earth.
For an object that is accelerating constantly,
,
where
is the initial velocity of the object,
is the final velocity of the object.
is its acceleration, and
is its displacement.
In this case,
is the same as the change in the ball's height:
. By assumption, this ball was dropped with no initial velocity. As a result,
. Since the ball is accelerating due to gravity,
.
.
In this case,
would be the velocity of the ball just before it hits the ground. Solve for
.
.
Answer:
(a) Magnitude of Vector = 207.73 m
(b) Direction = 65.48°
Explanation:
(a)
The formula to find out the magnitude of a resultant vector with the help of its x and y components is given as follows:

<u>Magnitude of Vector = 207.73 m</u>
(b)
For the direction of the vector we have the formula:

<u>Direction = 65.48°</u>
Answer:
It's like the Earth pulling on you and keeping you on the ground. That pull is gravity at work. Every object in the universe that has mass exerts a gravitational pull, or force, on every other mass. The size of the pull depends on the masses of the objects.
Explanation: