All categories

3 years ago

I need help with this question.

Mathematics

1 answer:

devlian [24]3 years ago

7 0

We can see that $a$ lies just before 0, $b$ lies between 2 and 3m and $c$ lies between 4 and 5. So, we have

$-1 < a < 0,\quad 2 < b < 3,\quad 4 < c < 5$

In particular, this implies that

$-1+4 < a+c < 0+5 \iff 3 < a+c < 5$

So, the correct order would be

$-2,\ b,\ a+c$

You might be interested in

Which of these points lies on the line described by the equation below? y - 4 = -2(x - 6)

ch4aika [34]

Y - y₁ = m(x - x₁)
y - 4 = -2(x - 6)
y - 4 = -2(x) + 2(6)
y - 4 = -2x + 12
+ 4 + 4
y = -2x + 16

The answer is D, (6, 4).

3 0

3 years ago

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

3 0

3 years ago

Terry has a savings account that pays 1.9% interest per year. Terry’s grandmother opened the account for him on his 10th birthda

noname [10]

Answer:

he will make 38 dollars by his 14th birthday

5 0

3 years ago

BRAINLIEST ANSWER TO FIRST ANSWERER!!!!!

krok68 [10]

Answer:

Option C $\frac{1}{2}(185\°-x\°)=76\°$

Step-by-step explanation:

we know that

The measurement of the <u>exterior angle</u> is the semi-difference of the arcs it comprises

$76\°=\frac{1}{2}(arc\ ST-arc\ XZ)$

we have

$arc\ ST=185\°$

$arc\ XZ=x\°$

substitute

$76\°=\frac{1}{2}(185\°-x\°)$

Rewrite

$\frac{1}{2}(185\°-x\°)=76\°$

4 0

3 years ago

Read 2 more answers

Can somebody help me find the area ?

aleksandrvk [35]

area of rectangle= length × width

= 19×33

= 627 sq units

3 0

2 years ago