Question

write and equation for the line that is parallel to the given line and that thale passes through the given point. y=3/4x-9 (-8 -18) ​

Answer 1

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{3}{4}$ x - 9 ← is in slope- intercept form

with slope m = $\frac{3}{4}$

• Parallel lines have equal slopes, hence

y = $\frac{3}{4}$ x + c ← is the partial equation of the parallel line.

To find c substitute (- 8, - 18) into the partial equation

- 18 = - 6 + c ⇒ c = - 18 + 6 = - 12

y = $\frac{3}{4}$ x - 12 ← equation of parallel line

Answer 2

Answer:

Step-by-step explanation:

The equation of a linear function in point-slope form is y – y1 = m(x – x1)

The point is A (x1 , y1)  

the slope is : m     the line that is parallel to the given line so : m = 3/4

passes through the given point (-8 -18)

so :  x1 = - 8   and y1 = -18

an equation is : y +18= 3/4(x +8)