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leonid [27]
3 years ago
9

10) A hydrobromic acid (HBr) solution has a molar concentration of 0.0085 M. Calculate the

Chemistry
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

ooooooooooooooooopp

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1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)
Mrac [35]

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂  +  2H₂SO₄     →     2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles =  300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and  H₂SO₄.

                   H₂SO₄         :       SrCl₂

                        2             :           1

                      3.1             :         1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

3 0
3 years ago
Hi what is 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
kogti [31]

Answer:

2e+130

Explanation:

5 0
3 years ago
Potassium carbonate dissolves as follows:
lara [203]

The 0.25 volume in liters of 1.0 M K_{2}CO_{3} solution is required to provide 0.5 moles of K(aq).

Calculation,

The Potassium carbonate dissolves as follows:

K_{2}CO_{3}(s) → 2K(aq) +CO_{3}^{-2} (aq)

The mole ratio is 1: 2

It means, the 1 mole K_{2}CO_{3} required to form 2 mole of K(aq).

To provide 0.5 mole of K(aq) = 1 mole ×0.5 mole /2 mole required by K_{2}CO_{3}.

To provide 0.5 mole of K(aq) ,0.25 mole required by K_{2}CO_{3}.

The morality of  K_{2}CO_{3} = 1 M = number of moles / volume in lit

The morality of  K_{2}CO_{3} =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

learn about moles

brainly.com/question/26416088

#SPJ4

5 0
2 years ago
Absolute zero is what temperature on the fahrenheit scale?
vampirchik [111]

Answer:

  • Absolute zero is - 459.67 °F

Explanation:

<u>1) Convert absolute zero to celsius:</u>

  • 0 K = - 273.15°C ( this is per definition of the scale)

<u>2) Convert - 273.15°C to Fahrenheit:</u>

  • T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=

  • T (°F) = - 273.15 × 1.8 + 32 = - 459.67 °F ← answer

8 0
2 years ago
Special characteristics of metals, like being shiny, are called A Descriptions B Phrases C Qualities D Properties
slega [8]
Answer:
d properties
i took a test on this before
8 0
3 years ago
Read 2 more answers
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