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3 years ago

A certain system absorbs 350 joules of heat and has 230 joules of work done on it what is the value of

1 answer:

7 0

According to the law of conservation of mass, the amount of BARIUM present of the reactants is the same as the amount present in the products (the precipitate).

(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt

(10.0 g) / (0.0480 mol) = 208.3 g/mol

So it must have been BaCl2, because the molar mass of Barium is 137 which leave 71 grams left. Since Barium is a +2 charge, it means the atom next to it must be twice. Chlorine mass is 35, which twice is 71

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A cation with a +4 charge has 26 neutrons and 18 electrons. What is the identity of the element?

Leya [2.2K]

Answer: Titanium has 22 protons

Explanation: If an atoms donates 4 electrons, it forms cation with charge +4. So original atom have 22 electrons and because atom is neutral, it has 22 protons. Number of neutrons does not matter, there are more neutrons than protons in heavier atoms.

3 0

2 years ago

What is the density of carbon dioxide gas if 0.196g occupies a volume of 100mL?

-BARSIC- [3]

We know that the equation for density is:

$D=\frac{m}{V}$

where D is the density, m is the mass in grams, and V is the volume.

Given two of the variables, we can then solve for density:

$D=\frac{0.196g}{100mL}= \frac{0.00196g}{mL}$

So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.

7 0

2 years ago

The equilibrium constant for the reaction

FinnZ [79.3K]

Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

Volume of solution = 1 L

Initial concentration of $Cl_2$ = $\frac{0.14mol}{1L}=0.14M$

The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

7 0

3 years ago

A sample of hydrogen gas will behave most like an ideal gas under conditions of?

fenix001 [56]

Conditions:
Low pressure and low temperature
Low pressure and high temperature
High pressure and low temperature
High pressure and high temperature

6 0

2 years ago

ASAP I AM GIVING BRAINLIEST PLEASEEEEEEEEE HELPPPPPPPPPPPPPPPPPP

zepelin [54]

Answer:

Explanation:

In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.

7 0

3 years ago