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Sav [38]
3 years ago
7

4.

Chemistry
2 answers:
Bad White [126]3 years ago
5 0

Answer:

thick, insulating fur

Explanation:

If an animal lives in a freezing climate, it makes sense logically that the animal would adapt and develop a layer of thick fur to keep its body insulated and maintain homeostasis.

Hope this helped and please consider a Brainliest! :)

user100 [1]3 years ago
4 0
Thick, insulating fur. Explanation: most of living species needs to be covered up in the cold. especially humans, we need coats for the cold just like animals need thick insulated fur for the cold.
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How is the Sun related to day and night and the change of seasons?
atroni [7]

Explanation:

As the Earth moves around the sun during a year, the northern half of the Earth is tilted towards the sun in the summer, making daytime longer than night. In winter, this reverses; the earth tilts away from the sun and nighttime becomes longer

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What is kinetic energy?
Natali5045456 [20]

Answer:

<h3>D energy of motion</h3>

Explanation:

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3 0
4 years ago
How many moles of potassium chloride and oxygen can be produced from 100.0g of potassium chlorate? The balanced equation is: 2 K
natka813 [3]

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 2 mols KCl/2 mols KClO₃= 0.8160 mols of KCl

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 3 mols O₂/ 2 mols KClO₃= 1.224 mols of O₂

try this

122.55 g is molar mass of potassium chlorate


4 0
3 years ago
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What moves across axons?
rewona [7]

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8 0
3 years ago
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I need some help with a long chemistry problem. Anything is appreciated!
Mkey [24]

Answer:

The CSI is wrong.  

Explanation:

1. Find the volume of the pool

The formula for the volume of a cylinder is  V = πr²h .

D = 12 m; h = 10 m

r = D/2 = (12 m/2) = 6.0 m

V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³

= 1.1. × 10⁶ L

2. Calculate the moles of OH⁻

n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻                                                                                                                                                                                                                                                                                                                              

3. Calculate the moles of acetic acid needed for neutralization

HA + OH⁻ ⟶ A⁻ + H₂O

The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.

4. Calculate the actual moles of acetic acid

You have four 5 L jugs of acetic acid pH 2 .

Volume = 20 L

[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹

(a) Set up an ICE table

                      HA + H₂O ⇌ A⁻  + H₃O⁺

I/mol·L⁻¹:          c                   0         0

I/mol·L⁻¹:     - 0.01             +0.01    +0.01

I/mol·L⁻¹:    c - 0.01             0.01     0.01

K_{\text{a}} = \dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}  = 1.76 \times 10^{-5}

(b) Calculate the concentration of acetic acid

\begin{array}{rcl}\dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}& = & 1.76 \times 10^{-5}\\\\\dfrac{0.01\times 0.01}{c}& = & 1.76 \times 10^{-5}\\\\1 \times 10^{-4} & = & 1.76 \times 10^{-5}c\\c & = & \dfrac{1 \times 10^{-4}}{1.76 \times 10^{-5}}\\\\ & = & \text{6 mol/L}\\\end{array}

The concentration of the acetic acid is 6 mol·L⁻¹

(c) Calculate the moles of acetic acid

n = \text{20 L} \times \dfrac{\text{6 mol}}{\text{1 L}} = \textbf{100 mol}

You have 100 mol of acetic acid.

The CSI is wrong.

You don't have enough acetic acid to neutralize the pool.

8 0
4 years ago
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