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Sav [38]
3 years ago
7

4.

Chemistry
2 answers:
Bad White [126]3 years ago
5 0

Answer:

thick, insulating fur

Explanation:

If an animal lives in a freezing climate, it makes sense logically that the animal would adapt and develop a layer of thick fur to keep its body insulated and maintain homeostasis.

Hope this helped and please consider a Brainliest! :)

user100 [1]3 years ago
4 0
Thick, insulating fur. Explanation: most of living species needs to be covered up in the cold. especially humans, we need coats for the cold just like animals need thick insulated fur for the cold.
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according to the law of conservation of , the number of atoms in the products of a chemical and equation must be balanced with t
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3 years ago
In which molecule the attraction between H and the atom to which it is bonded be the greatest
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I got the one you got to pick up my car stereo truck in my truck so I’m coming
5 0
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______ contributes to the nitrogen cycle by removing nitrogen from the air and converting it into a form that is usable by plant
umka21 [38]

Answer: Bacteria✅

Explanation:

4 0
2 years ago
hich of the following changes always leads to an increase in the rate constant for a reaction: Decreasing the temperature Decrea
GrogVix [38]

Answer:

Only one—(i), or (ii), or (iii)—increases the reaction rate.

Explanation:

<em>Which of the following changes always leads to an increase in the rate constant for a reaction?</em>

  • <em>Decreasing the temperature. </em>NO. A lower temperature leads to a slower reaction because the molecules have less energy to react.
  • <em>Decreasing the activation energy</em>. YES. According to the Arrhenius equation, the lower the activation energy, the higher the rate constant.
  • <em>Making the value of ΔE more negative</em>. NO. A more negative ΔE means a reaction is more spontaneous but not faster.
4 0
3 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
3 years ago
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