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Shkiper50 [21]
3 years ago
10

_________ liquids and gases exert a buoyant force.

Physics
2 answers:
NikAS [45]3 years ago
7 0

Answer:

Both liquids and gases exert a bouyant force when gravity is acting on them

Eduardwww [97]3 years ago
5 0

Answer:

C. Both

Explanation:

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Katen [24]
Visual aids are tools that help to make an issue or lesson clearer or easier to understand and know (pictures, models, charts, maps, videos, slides, real objects etc.). ... Visual aids are those devices which are used in classrooms to encourage students learning process and make it easier and interesting.
7 0
2 years ago
True or false question please help me out
Len [333]

Answer:

thats true

Explanation:

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2 years ago
A girl playing tug-of-war with her dog pulls the dog a distance of 8.0m by exerting a force at an angle of 18° with the horizont
AnnZ [28]

Answer:

25 N

Explanation:

Work is a product of force and perpendicular distance moved.

W=Fd where F is force exerted and d is perpendicular distance.

However, for this case, the distance is inclined hence resolving it to perpendicular so that it be along x-axis we have distance as dcos\theta

Therefore, W=Fdcos\theta

Making F the subject of the formula then

F=\frac {W}{dcos\theta} where \theta is the angle of inclination. Substituting 190 J for W then 18 degrees for \theta and 8 m for d then

F=\frac {190}{8cos18^{\circ}}\approx 25N

3 0
3 years ago
Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t
stepan [7]
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
F=ma
where F=-50 N is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
a= \frac{v_f^2-v_i^2}{2d}
where
v_f=0 is the final speed of the sled
v_i=5 m/s is the initial speed
d is the distance covered

By rearranging the equation, we find d:
d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m
3 0
3 years ago
When we touch things, how close do atoms get together? Or does anything touch anything else?? Full answer Please 50 - 100 words
kkurt [141]
Well, im pretty sure that when we do touch eachother, the atoms themselves are touching. idk if this is what ur looking for but hope this helps.
3 0
3 years ago
Read 2 more answers
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