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3 years ago

_________ liquids and gases exert a buoyant force.

Physics

2 answers:

NikAS [45]3 years ago

7 0

Answer:

Both liquids and gases exert a bouyant force when gravity is acting on them

Eduardwww [97]3 years ago

5 0

Answer:

C. Both

Explanation:

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What is the speed of sound at sea level?

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The speed of sound at sea level is 340.29 m/s (meters per seconds).

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4 years ago

if you jump from a window that is 2 meters up you will most likely break the bones in your legs when you land however on a tramp

Gemiola [76]

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4 years ago

A 61.0-kg person jumps from rest off a 10.0-m-high tower straight down into the water. Neglect air resistance. She comes to rest

9966 [12]

Answer:

Explanation:

In this case, law of conservation of energy will be implemented. It states that "the energy of the system remains conserved until or unless some external force act on it. Energy of the system may went through the conversion process like kinetic energy into potential and potential into kinetic energy.But their total always remain the same in conserved systems."

Given data:

Height of tower = 10.0 m

Depth of the pool = 3.00 cm

Mass of person = 61.0 kg

Solution:

Initial energy = Final energy

$U_{i} = (K.E) + U_{f}$

As the person was at height initially so it has the potential energy only.

$mg(h_{1} +h_{2}) = K.E + mgh_{2}$

$K.E = mgh_{1}$

$K.E = (61.0)(9.8)(10)\\K.E = 5978 J$

Lets find out the magnitude of the force that the water is exerting on the diver.

W =ΔK.E

$F.h_{2} = 5978\\$

$F = \frac{5978}{3}$

F = 1992.67 N

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3 years ago

If you had an unlimited amount of mass to hang, what would be the range of possible accelerations for the system?

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Answer:

The entire cart/hanging mass system follows the same law, ΣF = ma. This means that plotting force vs. acceleration yields a linear relationship (of the form y = mx).

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3 years ago

Consider a 2250-lb automobile clocked by law-enforcement radar at a speed of 85.5 mph (miles/hour). if the position of the car i

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As per law of Heisenberg uncertainty law

product of uncertainty in position and uncertainty in momentum will be constant

$\Delta x . \Delta P = \frac{h}{4\pi}$