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Paraphin [41]
3 years ago
7

In a lab,two pieces of cellphane tape are placed on a lab table. They are quickly ripped off the lab table. Which would you pred

ict would happen if the two pieces of tape were brought near each other?
Physics
1 answer:
galben [10]3 years ago
4 0

Answer:

they would repel each other

Explanation:

they have gained the same charge

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Which of the following is not part of the role of a forester
snow_tiger [21]
Since you provide no options, here are some role of the foresters :

- they develop sustainable forest practice
- They asses timber Quality
- They make sure that all harvesting activities followed the law's regulation
- They plan and supervise forestry project

your answer might be the one that isn't included above
3 0
4 years ago
Read 2 more answers
6. A ball rolled 125 m from the top of a hill to the bottom of a hill. How long
leva [86]
Time = distance / speed
T = 125/ 5
T = 25 meters per second
7 0
3 years ago
Coherent light with wavelength 608 nm passes through two very narrow slits, and the interference pattern is observed on a screen
Kipish [7]

Answer:

1.22 \mu m

Explanation:

In the double-slit interference, light passes through a double slit and produce a pattern of alternating bright and dark fringes on a distant screen. This pattern is due to the combined effect of the diffraction of each slit + the interference of the light coming from the two slits.

The condition to observe a maximum (bright fringe), so costructive interference, in the distant screen, is:

y=\frac{m\lambda D}{d}

where:

y is the distance of the m-th maximum from the central fringe

\lambda is the wavelength of the light used

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, we know that:

\lambda=608 nm=608\cdot 10^{-9}m is the wavelength of light used

D=3.00 m is the distance of the screen

y=4.84 mm = 4.84\cdot 10^{-3} m is the distance of the first maximum (first-order bright fringe) from the central pattern, so when

m = 1

Solving for d, we find the separation of the slits:

d=\frac{m\lambda D}{y}=\frac{(1)(608\cdot 10^{-9})(3.00)}{4.84\cdot 10^{-3}}=3.77\cdot 10^{-4} m

The first dark fringe on the screen instead is given by the formula

y'=\frac{(\frac{\lambda'}{2})D}{d}

where

\lambda' is the wavelength of the new light

Here we want the first dark fringe of the new light to be coincident to the first bright fringe of the previous light, so

y=4.84\cdot 10^{-3}m

Therefore, solving for \lambda',

\lambda'=\frac{2y'd}{D}=\frac{2(4.84\cdot 10^{-3})(3.77\cdot 10^{-4})}{3.00}=1.22\cdot 10^{-6} m = 1.22 \mu m

4 0
3 years ago
Is it possible to stop time
finlep [7]

Answer:

NO

Explanation:

NO ES POSIBLE

8 0
3 years ago
In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu
USPshnik [31]

Answer:

the effect would be 2w=btyh,3

Explanation:

5 0
3 years ago
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