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FrozenT [24]
3 years ago
6

The approximate rotation period of the Moon is: A. 1 day B. 1 week C. I month D. Infinite, since the Moon does not rotate, but k

eeps one face towards the Earth at all times.
Physics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

C. 1 month

Explanation:

The moon orbits around the earth once in a time of 27.322 days and it also takes about 27 days to orbit around its own axis. Due to this the moon is not seem to be spinning and it always seems still to observer who is observing from the Earth.

The moon takes about almost 1 month to make 1 revolution around the Earth . It also takes approximately the same time to make one rotation about its axis. This is why we always see the same face of the moon.

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The question states: two large, parallel conducting plates are 12cm
AnnZ [28]

Answer:

1. 24375 N/C

2. 2925 V

Explanation:

d = 12 cm = 0.12 m

F = 3.9 x 10^-15 N

q = 1.6 x 10^-19 C

1. The relation between the electric field and the charge is given by

F = q E

So, E=\frac{F}{q}

E=\frac{3.9 \times 10^{-15}}{1.6 \times 10^{-19}}

E = 24375 N/C

2. The potential difference and the electric field is related by the given relation.

V = E x d

where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.

By substituting the values, we get

V = 24375 x 0.12 = 2925 Volt

6 0
3 years ago
A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coe
Levart [38]

Answer:

Coefficient of static friction will be equal to 0.642  

Explanation:

We have given acceleration a=6.3m/sec^2

Acceleration due to gravity g=9.8m/sec^2

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to a=\mu g, here \mu is coefficient of static friction and g is acceleration due to gravity

So \mu =\frac{a}{g}=\frac{6.3}{9.8}=0.642

So coefficient of static friction will be equal to 0.642

3 0
3 years ago
Helppppppp pleaseeee
SVETLANKA909090 [29]

Answer: (Sorry, but I don't know how to calculate mass)

1. 15 N

2. 0.4921 \frac{ft}{s^2} (feet per second squared)

4. 150 N

5. 8.202 feet per second squared

3 0
2 years ago
A toy dart gun generates a dart with a momentum of 140 kg*m/s and a
irinina [24]

Answer:

35 kg

Explanation:

From the question,

Momentum (I) = mass (m) × velocity (v)

I = m×v................... Equation 1

Where m = mass, v = velocity

make m the subject of the equation

m = I/v.................... Equation 2

Given: I = 140 kgm/s, v = 4 m/s

Substitute these values into equation 2

m = 140/4

m = 35 kg

Hence the mass of the dart is 35 kg

6 0
3 years ago
Read 2 more answers
An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t
elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

\mu = \frac{f_0}{f_e}

Here,

\mu = Magnification

f_e = Focal length eyepieces

f_0 = Focal length of the Objective

Rearranging to find the focal length of the objective

f_0 = \mu f_e

Replacing with our values

f_0 = 7.5* 3.7cm

f_0 = 27.75cm

Therefore the focal length of th eobjective lenses is 27.75cm

5 0
3 years ago
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