The pressure exerted by a fluid solely relies on the depth or height of the fluid, its density, and the gravitational constant. These three are related in the equation:
Pressure = density x g x height
In the problem, point A is within the block inside the tank. The water above the block is assumed to be 0.6 meters. This gives a point A pressure of:
P = 1000 kg/m^3 * 9.81 m/s^2 * 0.6 m = 5,886 Pa or 5.88KPa
The options missing are;
A. Make only a few changes to the manipulated variable.
B. Identify any biases about the answer to the scientific question.
C. Include as many details as possible when writing the conclusion.
D. Share her ideas through peer review.
Answer:
B. Identify any biases about the answer to the scientific question.
Explanation:
Since the question is asking what can be done to improve the quality of the results, it means what can the scientist do to make sure that the result answers the question properly and has little or no biases.
Thus, looking at the options, the only one that comes close to actually improving on the quality of the results before finalizing is option B where the scientist is to identify any biases.
Answer:
a. There is a force on Jupiter toward the center of the orbit.
d. Jupiter is accelerating toward the center of the orbit.
Explanation:
Let us look at each of the choices one by one:
a. There is a force on Jupiter toward the center of the orbit.
True. The sun being at the center of Jupiter's orbit, pulls the planet towards it (providing the centripetal force), therefore, there exists a force on Jupiter toward the center of the orbit.
b. There is a force on Jupiter pulling it out from the center of the orbit.
Nope. The centripetal force due to gravity acts towards the center of the orbit.
c. There is a force on Jupiter in the direction of its motion.
Nope. There exists only the centripetal force acting towards the center of the orbit,
d. Jupiter is accelerating toward the center of the orbit.
Yes. Because of the centripetal force gravity provides, Jupiter is accelerating towards the center of the orbit, but it does not fall in because it has velocity perpendicular to the direction of its acceleration.
Answer:
past and past participle of catch.
Answer:
h = 2.087 m
Explanation:
Given
m₁ = 3 kg
v₁ = 20 m/s
m₂ = 2 kg
v₂ = - 14 m/s
In a completely inelastic collision the colliding objects stick together after the collision and move together as a single object.
In the given problem, lets assume that the balls of putty are initially moving along the y axis, upward direction being the positive y direction. And the collision occurs at the origin of the coordinate system.
We can apply the equation
vs = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)
⇒ vs = (3 kg*20 m/s + 2 kg*(- 14 m/s)) / (3 kg + 2 kg)
⇒ vs = 6.4 m/s (↑)
To calculate the maximum height h attained by the combined system of two balls of putty after the the collision, we use the expression for linear motion under gravity:
vf² = vi² - 2*g*h
where
vf = 0 m/s
g = 9.81 m/s²
vi = vs = 6.4 m/s
finally we get h:
h = vi² / (2*g)
⇒ h = (6.4 m/s)² / (2*9.81 m/s²) = 2.087 m
