1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveta [45]
3 years ago
8

A box is pulled up a rough ramp that makes an angle of 22 degrees with the horizontal surface. The surface of the ramp is the x-

plane.There is a free body diagram drawing on a block on a 22 degree incline with 5 force vectors. The first force is pointing up and parallel to the surface of the incline, labeled F Subscript T Baseline. The second force is pointing down and parallel to the surface of the incline, labeled F Subscript f Baseline = 14.8 N. The third force is pointing away from and perpendicular to the surface of the incline, labeled F Subscript N Baseline = 65 N. The fourth force is pointing into and perpendicular to the surface of the incline, labeled F Subscript g y Baseline. The fifth force is pointing straight down to the center of the earth, labeled F Subscript g Baseline = 70 N. There is another force parallel to the surface of the incline and down the hill starting at the tip of the F Subscript g y Baseline vector; it is labeled F Subscript g x Baseline.
What is the magnitude of the force of tension if the net force in the x direction of 98 N?


57 N

139 N

178 N

183 N

PLEASE EXPLAIN HOW YOU GOT ANSWER!

Physics
2 answers:
kifflom [539]3 years ago
8 0

Magnitude of the force  of tension: 139 N

Explanation:

The surface of the ramp here is assumed to be the positive x-direction.

To solve this problem and find the magnitude of the force of tension, we have to analyze only the situation along the x-direction, since the force of tension lie in this direction.

There are three forces acting along the x-direction:

  • The force of tension, F_T, acting up along the plane
  • The force of friction, F_f=14.8 N, acting down along the plane
  • The component of the weight in the x-direction, F_{gx}, acting down along the plane

We know that the magnitude of the weight is

F_g=70.0 N

So its x-component is

F_{gx}=F_g sin \theta =(70.0)(sin 22^{\circ})=26.2 N

The net force along the x-direction can be written as

F_x = F_T-F_f-F_{gx}

And therefore, since the net force is 98 N, we can find the magnitude of the force of tension:

F_T=F_x+F_f+F_{gx}=98+14.8+26.2=139 N

Learn more about inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

IrinaK [193]3 years ago
8 0

Answer:

139N

on edg

Explanation:

You might be interested in
Hurricane formation is rare within ________ degrees of the equator.
Free_Kalibri [48]
15 to 35 degrees of equator
3 0
3 years ago
What is different about the different parts of the electromagnetic spectrum
Archy [21]

Answer:

Each part of the spectrum has a different range of wavelengths (which correspond to frequency, color, and energy) at which you can find it.

4 0
3 years ago
Please help find the total resistance of these circuits!! I will mark brainliest if right!!
Elan Coil [88]

Answer:

If you know the total current and the voltage across the whole circuit, you can find the total resistance using Ohm's Law: R = V / I. For example, a parallel circuit has a voltage of 9 volts and total current of 3 amps. The total resistance RT = 9 volts / 3 amps = 3 Ω.

Explanation:

4 0
3 years ago
How is mercury barometer constructed ?<br>​
olganol [36]

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

  • A mercury barometer requires a tube which has one close end, and one open end.
  • Tube is placed upside down in a beaker in such a way so that one end open in the beaker and the other remain outside of the beaker.
  • The barometric liquid (mercury) is then filled in the tube by pouring mercury liquid in the beaker.

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

4 0
3 years ago
Two kids are playing on a newly installed slide, which is 3 m long. John, whose mass is 30 kg, slides down into William (20 kg),
yuradex [85]

Answer:

v=3.564\ m.s^{-1}

\Delta v =2.16\ m.s^{-1}

Explanation:

Given:

  • mass of John, m_J=30\ kg
  • mass of William, m_W=30\ kg
  • length of slide, l=3\ m

(A)

height between John and William, h=1.8\ m

<u>Using the equation of motion:</u>

v_J^2=u_J^2+2 (g.sin\theta).l

where:

v_J = final velocity of John at the end of the slide

u_J = initial velocity of John at the top of the slide = 0

Now putting respective :

v_J^2=0^2+2\times (9.8\times \frac{1.8}{3})\times 3

v_J=5.94\ m.s^{-1}

<u>Now using the law of conservation of momentum at the bottom of the slide:</u>

<em>Sum of initial momentum of kids before & after collision must be equal.</em>

m_J.v_J+m_w.v_w=(m_J+m_w).v

where: v = velocity with which they move together after collision

30\times 5.94+0=(30+20)v

v=3.564\ m.s^{-1} is the velocity with which they leave the slide.

(B)

  • frictional force due to mud, f=105\ N

<u>Now we find the force along the slide due to the body weight:</u>

F=m_J.g.sin\theta

F=30\times 9.8\times \frac{1.8}{3}

F=176.4\ N

<em><u>Hence the net force along the slide:</u></em>

F_R=71.4\ N

<em>Now the acceleration of John:</em>

a_j=\frac{F_R}{m_J}

a_j=\frac{71.4}{30}

a_j=2.38\ m.s^{-2}

<u>Now the new velocity:</u>

v_J_n^2=u_J^2+2.(a_j).l

v_J_n^2=0^2+2\times 2.38\times 3

v_J_n=3.78\ m.s^{-1}

Hence the new velocity is slower by

\Delta v =(v_J-v_J_n)

\Delta v =5.94-3.78= 2.16\ m.s^{-1}

8 0
3 years ago
Other questions:
  • If the change in enthalpy is -5074.3 kj, how much work is done during the combustion?
    7·1 answer
  • What is an item in which magnetic domains can be aligned and a magnetic field induced for a short period of time
    14·2 answers
  • Which of the following units could be used for the average speed of an object? A. kilometers per hour (km/hr) B. miles per hour
    7·1 answer
  • How plants are in the<br> Solora System
    9·2 answers
  • Watt which is a unit of power is equal to
    14·1 answer
  • A 1490-kg car is moving due east with an initial speed of 29.5 m/s. After 9.14 s the car has slowed down to 18.8 m/s. Find the m
    15·1 answer
  • Here you go.................
    14·2 answers
  • Which diagram best shows the results of removing heat from the original sample until it freezes?
    8·1 answer
  • HI I am taking a quiz and I need help it’s science o.o:
    14·1 answer
  • ¿por qué los buzos, cuando emergen con urgencia, deben exhalar continuamente durante el ascenso?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!