Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that
now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass
now from above equation
now we have
now the other force is given as
Answer:
Th spring is compressed by distance
Explanation:
Given:
Mass of block A=
Mass of block B=
variation of coefficient of friction with x,
spring constant=k
Distance covered on frictional surface=d
Taking block A and block B as a system , there is no external force acting on the system so the momentum can b conserved in horizontal direction.
Conservation Of Momentum
Now the blocks got stick together so both of them will pass through the frictional surface and will compress the spring together.
Work done by friction
Work done by spring
So applying Work Energy Theorem before the blocks moves to the frictional surface and when the blocks comes to rest by co pressing the spring by distance x.
Work done by all the spring +work done by friction=change in kinetic Energy of the system of blocks.
1. The magnitude of the gravitational force between the Earth and an m is 54.1 N.
2. The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
<h3>
Gravitational force between Earth and mass, m</h3>
The gravitational force between Earth and mass, m is calculated as follows;
F(Earth) = Gm₁m₂/R²
F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²
F(Earth) = 54.1 N
<h3>
Gravitational force between Moon and mass, m</h3>
F(moon) = Gm₁m₂/R²
F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²
F(moon) = 1.91 x 10⁻⁴ N
<h3>
Gravitational force between Sun and mass, m</h3>
F(sun) = Gm₁m₂/R²
F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²
F(sun) = 0.0324 N
<h3>Ratio of F(sun) to F(moon)</h3>
= 0.0324/1.91 x 10⁻⁴
= 169.6
Thus, the magnitude of the gravitational force between the Earth and an m is 54.1 N.
The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
Learn more about gravitational force here: brainly.com/question/72250
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