Answer:
F = Force (Measured in Newtons, N), m = Mass (Measured in kilograms, kg), and a = acceleration (Measured in metres per second squared, ![m/s^{2}](https://tex.z-dn.net/?f=m%2Fs%5E%7B2%7D)
Explanation:
This is Newton's Second Law!
Hope this helps!
PLS mark as brainliest, hope this helps!
Answer:
velocity : velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes. The average velocity is the displacement or position change (a vector quantity) per time ratio.
speed : Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time. ... An object with no movement at all has a zero speed.
Explanation:
Answer:
<h2>4</h2>
Explanation:
Mechanical advantage is defined as the ratio of the load to the effort applied to raise the load. If minimal effort is used to overcome a much larger load, that is when we have what is called mechanical advantage i.e a machine has been used to our advantage.
Mathematically, MA = Load/Effort
Given parameters
Load = 160N
Effort = 40N
Required
Mechanical Advantage
Using the formula above
MA = 160N/40N
MA = 4
<em>advantage</em>
Question:
A roller-coaster vehicle has a mass of 500 kg when fully loaded with passengers. If the vehicle has a speed of 20.0 m/s at point A, what is the force exerted by the track on the vehicle at this point?
<em>See attachment</em>
Answer:
33700 Newton
Explanation:
Given
![m = 500kg\\v = 24.0m/s\\r=10m](https://tex.z-dn.net/?f=m%20%3D%20500kg%5C%5Cv%20%3D%2024.0m%2Fs%5C%5Cr%3D10m)
First, we determine the forces acting on mass m.
They are: the force exerted by the track (Fn) and the weight of the vehicle (W)
So, the net force is:
![F_{net} = F_n - W](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20F_n%20-%20W)
![W=mg](https://tex.z-dn.net/?f=W%3Dmg)
So:
![F_{net} = F_n - mg](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20F_n%20-%20mg)
Make Fn the subject
Fnet is calculated as:
--- i.e. the centripetal force
So:
![F_n = F_{net} + mg](https://tex.z-dn.net/?f=F_n%20%3D%20F_%7Bnet%7D%20%2B%20mg)
![F_n = \frac{500 * 24^2}{10} + 500 * 9.8](https://tex.z-dn.net/?f=F_n%20%3D%20%5Cfrac%7B500%20%2A%2024%5E2%7D%7B10%7D%20%2B%20500%20%2A%209.8)
![F_n = 33700N](https://tex.z-dn.net/?f=F_n%20%3D%2033700N)
Answer:
I think c is the answer but I have a little concern on d too