Answer:
Each coins are quarters of <u>6</u>, nickels of <u>18</u> and the dimes of <u>9</u>.
Step-by-step explanation:
<u><em>There is a mistake in question.</em></u>
The question must be:
A collection of 33 coins having dimes quarters and nickels, <u>there are 3 times as many nickels as quarters, and one-half as many dimes as nickels</u>, all of the coins equal $3.30 how many coins of each kind are there?
Now, to find the number coins of each.
Let the quarters be 
.
Nickels be 
.
And the dimes be 
.
So, the total collection of coins are:
On adding the fractions we get:
Multiplying both sides by 2 we get:
Dividing both sides by 11 we get:
Thus, quarters = 6.
Nickels = 
Dimes = 
Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.
Scale factor= length of the copied figure /length of the original
You count the units from the graph
Figure A(the original) is 6
Figure B ( the copied figure) is 2
=2/6
<span>1. slope = (n-k)/(m-j)
2. slope = (n-k))/(m-j)
3. P" = (m,n+e-3)
1. The slope of a line is the ratio between the change in y in regard to the change in x. Since we have two known points on the line r, we can simply subtract their respective x and y coordinates and divide. So
slope = (n-k)/(m-j)
One thing to pay attention to is to do the subtraction IN THE SAME ORDER. The actual order doesn't matter as long as it's the same for both top and bottom. For instance, this is another equation for the slope that's just as valid.
slope = (k-n)/(j-m)
2. This is the exact same way. Just subtract the different y coordinates and divide by the difference between the x coordinates.
slope=((n+e)-(k+e))/(m-j)
Now because of the associative property, we can do some rearrangement of the expression to get
slope=(n+e-k-e))/(m-j)
and the "e" terms cancel each other, giving
slope=(n-k))/(m-j)
And you'll see that the slope is the same as for problem #1 above.
3. For this, let's look at the coordinates of point P'
P' = (m,n+e)
Since we want to move it 3 units down, just subtract 3 from the y coordinate, so
P" = (m,n+e-3)</span>
