Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
f(x) = -3x - 2
F(0)=-2
F(1)= -5
Domain R
Range R
Step-by-step explanation:
Answer:
9 1/11
Step-by-step explanation
I just used Calculator Soup, it helps me with problems that are extremely hard for me to do (look it up)
we know that
acceleration due to gravity is 9.8m/s^2
so, we get

and acceleration will always be constant
we know that
integral of acceleration is velocity
so, we can integrate both sides


we are given
v(0)=35m/s
we can use it and find C



now, we can plug it back

we know that
integral of velocity is height
we can integrate it again



now, we have
s(0)=6
we can use it and find C


now, we can plug back C

and we get
.............Answer
Answer:
My solution is I don't have solutions