Answer: m = -
Step-by-step explanation:
I know this because I'm built different (FR FR This answer is correct)
Answer:
x<3
Step-by-step explanation:
Ending Amount = Beginning Amount * e^k*t
5 grams = 100 grams * e^-.00043 * years
We have to solve the equation for "years"
(You can find the formula here: http://www.1728.org/halflif2.htm
or you can just read the next line
time = natural log (bgng amt / endg amt) / k
time = natural log (100 / 5) / .00043
time = natural log (20) / .00043
time = 2.9957322736 / .00043
time =
<span>
<span>
<span>
6,967</span></span></span><span> years
</span>
We should double-check this.
First, we need the half-life
k = ln(.5) / half-life
half-life = <span>-.693147 / -.00043
half-life = 1,612 years
Now let's see how many half-lives that is:
</span><span>6,967 / 1,612 years = 4.2 half-lives
So basically, after 4 half-lives the mass should go from
100
50 1 half life
25</span><span><span> 2 half lives</span>
12.5 </span><span>3 half lives
</span> 6.25 <span>4 half lives</span>
6.25 is very close to 5 grams so we can assume we have calculated correctly.
The answer is $5,000.73.
Explanation: If one Canadian dollar bill is $1.00 and a Trinidad’s $1.00 is $2.73 then that means if you wanna convert it you have to double the amount including the €73 and you have 2,500 you need to double the amount then add the remaining €73.
Answer:
We want to test the the claim that in general, 10% of students repeat a course and thats what we want to verify so then the system of hypothesis are:
Null hypothesis:
Alternative hypothesis
And the best option for this case is given:
d) H0:p=0.1 vs. H1:p 0.1
Step-by-step explanation:
For this case we have the folloing info:
number of people repeating the class
the sampel size selected
the estimated proportion of people repeating the class
We want to test the the claim that in general, 10% of students repeat a course and thats what we want to verify so then the system of hypothesis are:
Null hypothesis:
Alternative hypothesis
And the best option for this case is given:
d) H0:p=0.1 vs. H1:p 0.1 .