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LenKa [72]
3 years ago
6

Hello, can someone pls help me ty!​

Chemistry
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
The answer is A. hope this helps:)
Rudiy273 years ago
4 0

Answer:

The answer is A

Explanation:

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E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution​
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18

Explanation:

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5 0
3 years ago
A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta
melomori [17]
Cao +  H2O  ---->Ca(OH)2
Calculate   the  number  of  each   reactant  and  the  moles  of  the  product
that  is
moles = mass/molar mass
The  moles  of  CaO=  56.08g/  56.08g/mol(molar  mass  of  Cao)=  1mole
the  moles  of  water=  36.04 g/18  g/mol=  2.002moles
The   moles  of Ca (OH)2=74.10g/74.093g/mol= 1mole

 The  mass  of differences  of  reactant  and  product  can   be  therefore 
 explained  as 
 1  mole   of  Cao  reacted  completely   with   1  mole   H2O  to  produce  1 mole  of  Ca(OH)2. The  mass  of  water   was  in  excess  while  that  of  CaO  was  limited

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3 years ago
PLEASE HELP!!
LUCKY_DIMON [66]

Answer:

5.1 - 2.3685 = 2.7315 \\

3 0
2 years ago
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