gBe sure to answer all parts. Nicotine can be made when the following ammonium salt is treated with Na2CO3. Determine a stepwise
1 answer:
Answer:
Kindly check the attached pictures.
Explanation:
For the reaction between ammonium salt and Na2CO3, in the reaction mechanism, there are going to be four steps for the production of nicotine. The chemical species to monitor here are the Na2CO3 and the starting material which has the amine group attached to it.
STEP ONE: Dissociation of the Na2CO3.
Na2CO3 <=========> 2Na^+ + CO3^2-
STEP TWO: (will be shown in the attached picture). It is the abstraction of H^+ from the amine in the starting material.
STEP THREE: (will be shown in the attached picture). It is the formation of a cyclic compound due to nucleophilic reaction.
STEP FOUR: (will be shown in the attached picture). It involve the the deprotonation and this is the final phase.
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Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.
BCA table:
2O ⇒
+
B 0.13 0 + 0
C -0.13 0.065 + 0.065
A 0 0.065
Explanation:
Balanced equation for water decomposition into hydrogen and oxygen gases
2O ⇒
+
B 0.13 0 + 0
C -0.13 0.065 + 0.065
A 0 0.065
Number of moles of water =
mass = 2.5 grams
atomic mass= 18 grams
number of moles can be known by putting the values in the formula,
n =
= 0.13 moles
2 moles of water gives one mole of oxygen on decomposition
so, 0.13 moles of water will give x moles of oxygen on decompsition
=
x = 0.065 moles of oxygen will be formed.
moles to gram will be calculated as
mass =number of moles x atomic mass
= 0.065 x 16
= 1.04 grams of oxygen.