gBe sure to answer all parts. Nicotine can be made when the following ammonium salt is treated with Na2CO3. Determine a stepwise
1 answer:
Answer:
Kindly check the attached pictures.
Explanation:
For the reaction between ammonium salt and Na2CO3, in the reaction mechanism, there are going to be four steps for the production of nicotine. The chemical species to monitor here are the Na2CO3 and the starting material which has the amine group attached to it.
STEP ONE: Dissociation of the Na2CO3.
Na2CO3 <=========> 2Na^+ + CO3^2-
STEP TWO: (will be shown in the attached picture). It is the abstraction of H^+ from the amine in the starting material.
STEP THREE: (will be shown in the attached picture). It is the formation of a cyclic compound due to nucleophilic reaction.
STEP FOUR: (will be shown in the attached picture). It involve the the deprotonation and this is the final phase.
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Answer:
0.805 M.
Explanation:
Hello!
In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:
Next, since the volume is 0.2500 in liters, the molarity turns out:
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