All categories

3 years ago

Acetylcholine binds to its receptor in the sarcolemma and triggers __________.

Chemistry

1 answer:

gladu [14]3 years ago

6 0

Answer:

b. The opening of ligand-gated cation channels

Step-by-step explanation:

When an acetylcholine ligand molecule binds to its receptor in the sarcolemma, it triggers a conformational change.

A "gate" in the receptor opens and allows Na⁺ ions to pass through a channel into the muscle fibre.

Hence the term ligand-gated cation channel.

You might be interested in

The length of the school's gymnasium is 30 meters long. How many centimeters long is the school's gymnasium

aleksley [76]

Answer:

The answer to your question is: 3000 cm

Explanation:

30 meters long to cm

We can use a rule of three to solve it

We know that 1 meter ------------------ 100 cm

30 meters ---------------- x

x = 30(100)/1 = 3000 cm

5 0

3 years ago

Read 2 more answers

That my last Q8 A , can someone help me with

DENIUS [597]

The first whistle is louder while the second whistle has a higher pitch
Loud vs high

3 0

2 years ago

Read 2 more answers

which tool was mostly likely used in a procedure if the lab report shows that approximately 300 ml of water was used

DiKsa [7]

it is most likely a beaker, beacuse 300ml is quite a large volume. Otherwise, it would be a measuring cylinder or pippette

7 0

3 years ago

Please help!! Why is the following Electron Configuration incorrect for Aluminium?

Margarita [4]

Answer:

3s^1 would be 3s^2

Explanation:

5 0

3 years ago

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

$2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3$

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol$

The given chemical equation follows:

$2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3$

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = $\frac{3}{2}\times 0.467=0.7005mol$ of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

$0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g$

Hence, the theoretical yield of copper is 44.48 grams

4 0

4 years ago