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rjkz [21]
3 years ago
15

Acetylcholine binds to its receptor in the sarcolemma and triggers __________.

Chemistry
1 answer:
gladu [14]3 years ago
6 0

Answer:

b. The opening of ligand-gated cation channels

Step-by-step explanation:

When an acetylcholine ligand molecule binds to its receptor in the sarcolemma, it triggers a conformational change.

A "gate" in the receptor opens and allows Na⁺ ions to pass through a channel into the muscle fibre.

Hence the term ligand-gated cation channel.

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Which of the following is a type of kinetic energy.
dexar [7]
Kinetic energy is energy in motion. B, a rolling ball would be your answer because a rolling ball is energy that is moving. The rest of the answers are wrong because the actions do not use kinetic energy.
6 0
3 years ago
An experiment requires 40.0g of ethylene glycol, a liquid whose density is 1.114 g/mL. Rather than weigh the sample on a balance
uranmaximum [27]
Density= mass/volume
volume=mass/density
volume= 40.0g/1.114g per mL
volume= 35.90664273 mL
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6 0
3 years ago
A water sample has a pH of 8.2 and a bicarbonate concentration of 97 mg/L. What is the alkalinity of the sample in moles/L and i
goldfiish [28.3K]

Answer:6.94

Explanation:

Molar mass of CaCO3=40+12+16×3

=40+12+48=100g/mol

Moles=mass of substance/molar mass

=97mg/100g=0.097/100=0.00097moles/L.

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P.s it's log to base e

3 0
3 years ago
Question
madam [21]

Answer:

The specific heat of the metal is 2.09899 J/g℃.

Explanation:

Given,

For Metal sample,

mass = 13 grams

T = 73°C

For Water sample,

mass = 60 grams

T = 22°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that , water sample temperature changed from  22°C to 27°C and metal sample temperature changed from 73°C to 27°C.

Since, Specific heat of water = 4.184 J/g°C

Let Cp be the specific heat of the metal.

Substituting values,

(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)

By solving, we get Cp =

Therefore, specific heat of the metal sample is 2.09899 J/g℃.

5 0
3 years ago
A motorcycle travel at 6.0 m/s. After 3.0 second, the motorcycle travel at 15.0 m/s. Which of the following was the average acce
Lerok [7]

Hello!

\large\boxed{a = 3m/s^{2}}

Use the following equation to solve for the average acceleration of the motorcycle:

a = \frac{v_{f}-v_{i}}{t}

Plug in the given final, initial velocities, and the time:

a = \frac{15-6}{3}\\\\a = \frac{9}{3}\\\\a = 3m/s^{2}

7 0
3 years ago
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