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Vlada [557]
4 years ago
13

Interquartile range (IQR)

Mathematics
2 answers:
Lynna [10]4 years ago
7 0

Answer:7.3

Step-by-step explanation:

The data from least to greatest is 2.8,4,4.3,6,7.5,8.5,9,11.6,12,12.1

Oduvanchick [21]4 years ago
4 0

Answer:

6

Step-by-step explanation:

Khan Academy

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Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
4 years ago
Algebra
vladimir2022 [97]
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together. 
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12 
6 + 6 = 12
12 = 12 <- this works! 

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
5 0
3 years ago
Read 2 more answers
F(x)=x^2-5 and g(x)=3x+1 then f(g(2))
LuckyWell [14K]

Answer:

f(g(2)) = 44

Step-by-step explanation:

g(2) = 3(2) + 1 = 7

Plug 7 into f(x) since g(2) = 7

f(7) = 7² - 5 = 44

f(g(2)) = 44

8 0
3 years ago
Graph the solution to the inequality<br> |y+5|&gt; 2
kirill [66]

Answer:

y>-3 y>-7

Step-by-step explanation:

-(y+5)>2

y<-7

7 0
4 years ago
42 is 30% of what number??? Add work plz
romanna [79]
X - the number

30\% x =42 \\&#10;\frac{30}{100}x=42 \\&#10;\frac{3}{10}x=42 \\&#10;x=42 \times \frac{10}{3} \\&#10;x=\frac{420}{3} \\&#10;x=140

42 is 30% of 140.
7 0
3 years ago
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