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lapo4ka [179]
3 years ago
13

Probability

Mathematics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

0.8

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given the expression:

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First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

8 0
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Step-by-step explanation:

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Step-by-step explanation:

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