M/sec = 112 km / 1 hr / 1 min / 1000 meters
hr / 60 min / 60 sec / 1 km
So the answer is = 31.1 meters/sec
77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 ×
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Calculate the moles of 5.00g of glucose.
Given mass = 5.00g
The molar mass of glucose = 180.156 g/mol
Moles =0.02775372455
The quantity of energy released to a person by eating 5.00g of glucose in a candy.
0.02775372455 x 2802.5 kJ
77.77981305 kJ =77.78 kJ
Hence, 777.78 kJ of energy is released.
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Answer:
The correct answer is 199.66 grams per mole.
Explanation:
Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,
R1/R2 = √ M2/√ M1
Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.
Rate Q/Rate N2 = √M of N2/ √M of Q
The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67
Now putting the values we get,
rate of N2/2.67/rate of N2 = √28/ √M of Q
√M of Q = √ 28 × 2.67
M of Q = (√ 28 × 2.67)²
M of Q = 199.66 grams per mole
Answer: Artificial transmutation may occur in machinery that has enough energy to cause changes in the nuclear structure of the elements. This releases, on average, 3 neutrons and a large amount of energy. The released neutrons then cause fission of other uranium atoms, until all of the available uranium is exhausted.
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