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adell [148]
3 years ago
12

How to calculate moles

Chemistry
2 answers:
blondinia [14]3 years ago
8 0

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

ValentinkaMS [17]3 years ago
6 0

Answer:

Number of moles : Mass (g) ÷ relative atomic mass

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If a reaction starts with 0.480 mol Mg how many moles of silver are produced
cupoosta [38]
The ratio for mg and ag is 1:2 therefore, 0.96 mole silver is produced, use the conversation method.
5 0
3 years ago
Consider the data presented below. time (s) 0 40 80 120 160 moles of a 0.100 0.067 0.045 0.030 0.020 part a part complete determ
Whitepunk [10]
To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows 
time         0         40        80       120       160
moles    0.100   0.067  0.045    0.030    0.020


Q1)
for the first 40 s change of moles ;
      = -d[A] / t
      = - (0.067-0.100)/40s
      = 8.25 x 10⁻⁴ mol/s
for the next 40 s
      = -(0.045-0.067)/40
      = 5.5 x 10⁻⁴ mol/s
the 40 s after that
      = -(0.030-0.045)/40 s 
     = 3.75 x 10⁻⁴ mol/s
k - rate constant
and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ   -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation. 
Since this is a first order reaction,
b = 1
therefore the reaction is 
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
   = 8.25 x 10⁻³ s⁻¹

7 0
3 years ago
When 2,4-hexadiene is protonated, a resonance-stabilized secondary allylic carbocation is formed. Draw the curved arrow notation
NemiM [27]

Answer:see the image for the structure of the allylic carbocation

Explanation:

When 2,4-hexanediene is protonated at the 5-position as shown in the image, a carbonation is formed which can be stabilized by resonance. The positive charge can be found on carbon 4 or carbon 2 due to resonance of the allylic carbonation. The both structures are shown and electron movements were depicted using curved arrow notation in the structures shown in the image attached.

4 0
3 years ago
The bonding electrons in a non-polar compound are:
lara31 [8.8K]
Its A) Shared equally
Non-polar bonds are a type of chemical bond where two atoms share a pair of electrons with each other.
3 0
3 years ago
2 C2H2 + 5 O2<br> 2 H2O + 4 CO2 <br> what reaction type
Alexxx [7]

Answer:

Combustion reaction

General Formulas and Concepts:

<u>Chemistry</u>

  • Synthesis Reactions: A + B → AB
  • Decomposition Reactions: AB → A + B
  • Single-Replacement Reactions: A + BC → AB + C
  • Double-Replacement Reactions: AB + CD → AD + BC

Explanation:

<u>Step 1: Define</u>

2C₂H₂ + 5O₂ → 2H₂O + 4CO₂

<u>Step 2: Identify</u>

Any organic molecule reacting with oxygen to produce water and carbon dioxide is a combustion reaction.

We also see from the RxN that is is a double replacement reaction.

5 0
2 years ago
Read 2 more answers
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