The rate of diffusion change would increase if the PO₂ in the capillaries was 40 mmHg and the PO₂ in the muscle cell changed from 40 to 20 mmHg.
Simple diffusion is the movement of molecular substances from a region of higher concentration to lower concentration. The mechanism with which the movement of O₂ travels from the blood to the body tissues takes place with the use of simple diffusion.
Now, if PO₂ changes from 40 → 20 mmHg in the muscle cells, and the PO₂ in the blood = 40mmHg. It implies that the pressure gradient(P) has increased. As such, there is an increase in the rate of diffusion of oxygen from the blood to muscle cells.
Learn more about diffusion here:
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<span>energy provided=13.4 eV
energy released=0.7 eV
energy absorbed = 12.7eV
initial energy= -13.6eV [ground state]
final energy = -13.6+12.7 = -0.9 eV
This energy corresponds to n=4 in hydrogen atom</span>
Answer:
There are 140.9 grams in 2.393*10²⁴ aotms of Cl.
Explanation:
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?
amount of moles= 3.973
If the molar mass of Cl is 35.453 
, then the amount of mass that contains 3.973 moles can be calculated as:
3.973 moles*35.453 = 140.85 grams ≅ 140.9 grams
<u><em>There are 140.9 grams in 2.393*10²⁴ aotms of Cl.</em></u>
Answer:
Explanation:
Well the gas is the fuel for the flame of course. The collision theory comes into play when the gas turns on, chemicals collide with one another. Then reactions occur causing the flame. Then when you take away the fuel, the flame stops because there is no atoms or molecules to come together/collide with one another.
Sorry if its wrong or doesn't make sense... Wish you the best of luck on whatever your doing!
Answer:
![[A_0]=10\ mg](https://tex.z-dn.net/?f=%5BA_0%5D%3D10%5C%20mg)
![[A_t]=0.08245\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D0.08245%5C%20mg)
Explanation:
Given that:
Half life = 10.4 hours
Where, k is rate constant
So,
The rate constant, k = 0.06664 hour⁻¹
Time = 24 hours
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t = 2 mg
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration = ?
So,
![2\ mg=[A_0]\times e^{-0.06664\times 24}](https://tex.z-dn.net/?f=2%5C%20mg%3D%5BA_0%5D%5Ctimes%20e%5E%7B-0.06664%5Ctimes%2024%7D)
Now, time = 3 days = 3*24 hours = 72 hours ( 1 day = 24 hours)
Thus,
![[A_t]=10\times e^{-0.06664\times 72}\ mg=0.08245\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D10%5Ctimes%20e%5E%7B-0.06664%5Ctimes%2072%7D%5C%20mg%3D0.08245%5C%20mg)
