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3 years ago

How many grams is 2.393 x 10^24 atoms of CI

Chemistry

1 answer:

Iteru [2.4K]3 years ago

7 0

Answer:

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?

$amount of moles=\frac{2.393*10^{24} *1 mole}{6.023*10^{23} }$

amount of moles= 3.973

If the molar mass of Cl is 35.453 $\frac{g}{mole}$ , then the amount of mass that contains 3.973 moles can be calculated as:

3.973 moles*35.453 $\frac{g}{mole}$ = 140.85 grams ≅ 140.9 grams

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

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What is the ph (to nearest 0.01 ph unit) of a solution prepared by mixing 58.0 ml of 0.0179 m naoh and 60.0 ml of 0.0294 m ba(oh

Nina [5.8K]

Answer: -

12.59

Explanation: -

Strength of NaOH = 0.0179 M

Volume of NaOH = 58.0 mL = 58.0/1000 = 0.058 L

Number of moles = 0.0179 M x 0.058 L

= 1.04 x 10⁻³ mol

Mol of [OH⁻] given by NaOH = 1.04 x 10⁻³ mol

Strength of Ba(OH)₂ = 0.0294 M

Volume of Ba(OH)₂ = 60.0 mL = 60.0/1000 = 0.060 L

Number of moles = 0.0294 M x 0.060 L

= 1.76 x 10⁻³ mol

Mol of [OH⁻] given by Ba(OH)₂ =2 x 1.76 x 10⁻³ mol

Total [OH⁻] = 1.04 x 10⁻³ mol + 2 x 1.76 x 10⁻³ mol

= 4.56 x 10⁻³ mol

Total volume of the mixture = 58.0 + 60.0

= 118.0 mL

118.0 mL of the solution has 4.56 x 10⁻³ mol [OH⁻]

1000 mL of the solution has $\frac{4.56 x 10-3 mol x 1000mL }{118 mL}$

= 0.0386 mol

Using the relation

pOH = - log [OH-]

= - log 0.0386

= 1.41

Using the relation

pH + pOH = 14

pH = 14 - 1.41

= 12.59

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3 years ago

As the deapth of the ocean increases the population of ocean creatures..

Trava [24]

Answer:

( A ) Increases

Explanation:

More room, basically means more creatures. Like in a bedroom, you can only fit amount of people if its small the ocean is like that with depth.

Hopefully this makes sense???

3 0

3 years ago

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What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) => 2

zavuch27 [327]

Answer: The mass of iron (II) oxide that must be used in the reaction is 30.37

Explanation:

The given chemical reaction follows:

$6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ$

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, $\frac{6}{635}\times 44.7=0.423mol$ of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

$0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g$

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

7 0

4 years ago

As k2o dissolves in water,the oxide ion reacts with water molecules to form hydroxide ions. write the molecular and net ionic eq

leva [86]

Solution:

The molecular equation is:

$K_2O(aq.)+H_2O(l)\rightarrow 2KOH(aq.)$

Now, the oxide ion reacts with water to produce hydroxide ions,

The ionic equation is:

$2K^+(aq.)+O^{2-}(aq.)+H_2O(l)\rightarrow 2K^+(aq.)+2OH^-(aq.)$

The $2K^+$ ions are present on both the sides, so the net ionic equation becomes,

$O^{2-}(aq.)+H_2O(l)\rightarrow 2OH^-(aq.)$

Now, to determine acid and base, we will look at the definitions

Acid: It is defined as proton donor that is it donates $H^+$ ions.

Base: It is defined as proton acceptor that is it accepts $H^+$ ions.

In the ionic equation, water is donating $H^+$ ions to $O^{2-}$ therefore it acts as an acid and oxide ion acts as a base.

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3 years ago

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Which displacement reaction is most likely to occur? Use the resources to help you. A. BaCl2 + Ca → CaCl2 + Ba B. BaCl2 + Sr → S

umka2103 [35]

Correct part is C.

Explanation: This question can be easily explained with the help of reactivity series.

The metal which lies below in the reactivity series CANNOT displace the metal which lies above it. Similarly if the metal lies above in the reactivity series, it CAN displace the metal lying low in the series.

In A part, the reaction follows

$BaCl_2+ Ca\rightarrow CaCl_2+Ba$

Here Ca metal lies low in the series than Ba, therefore it cannot displace Ba metal in the reaction.

In B part ,the reaction follows

$BaCl_2+Sr\rightarrow SrCl_2+Ba$

Here also Sr metal lies low in the series, therefore it cannot displace Ba.

In C part, the reaction follows

$BaCl_2+2Na\rightarrow 2NaCl+Ba$

Here Na metal lies above in the series than Ba, therefore it can easily displace Ba in the reaction and will lead to form NaCl as a product.

In D part, the reaction follows

$BaCl_2+Mg\rightarrow MgCl_2+Ba$

Here Mg lies low in the series, therefore it cannot displace Ba in the reaction.

You can use the image attached.

6 0

4 years ago