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3 years ago

How many grams is 2.393 x 10^24 atoms of CI

Chemistry

1 answer:

Iteru [2.4K]3 years ago

7 0

Answer:

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?

$amount of moles=\frac{2.393*10^{24} *1 mole}{6.023*10^{23} }$

amount of moles= 3.973

If the molar mass of Cl is 35.453 $\frac{g}{mole}$ , then the amount of mass that contains 3.973 moles can be calculated as:

3.973 moles*35.453 $\frac{g}{mole}$ = 140.85 grams ≅ 140.9 grams

<u><em>There are 140.9 grams in 2.393*10²⁴ aotms of Cl.</em></u>

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Answer:

Explanation:

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MB=90-3E

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