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2 years ago

5

Jennifer has measured the amount of rain water in several different beakers for a science experiment. The amounts she measured a

re shown in the data table below

1 answer:

Lunna [17]2 years ago

4 0

There is no table to use for this problem therefore it is impossible to answer.

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If AB=BA= I then write the relation between matrix A and matrix B

butalik [34]

Answer:

If AB = BA = I, then B is inverse of A and vice-versa.

Step-by-step explanation:

Given: AB = BA = I

To find: The relation between matrix A and B.

If AB = BA = I, then B is called the inverse matrix of A and is denoted by $A^{-1}$ .

In that case, A is said to be invertible.

Also, if B is the inverse of A, then A is also the inverse of B.

Hence, the relation between A and B is that both are inverse of each other.

6 0

2 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
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hope this helps!

3 0

2 years ago

Do these side lengths make a right triangle? 7, 13, and 218√

Nana76 [90]

Am not sure but maybe no because i learned it 2 month ago

6 0

2 years ago

Read 2 more answers

Which one is greater root of 3 or 2?

DENIUS [597]

The root of 3 is greater

8 0

2 years ago

Read 2 more answers

Evaluate the expression \dfrac{x^5}{x^2} x 2 x 5 start fraction, x, start superscript, 5, end superscript, divided by, x, squa

Elza [17]

Answer:

8

Step-by-step explanation:

Fill in the variable value and do the arithmetic.

$\dfrac{2^5}{2^2}=\dfrac{32}{4}=8$

___

Of course, the fraction can be simplified first:

$\dfrac{x^5}{x^2}=x^{5-2}=x^3\\\\2^3=8$

7 0

2 years ago