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Molodets [167]
3 years ago
10

The most negative electron affinity is most likely associated with which type of atoms?

Chemistry
2 answers:
Llana [10]3 years ago
7 0

Explanation:

elements are based on electrical conductivity

Goshia [24]3 years ago
3 0

Answer:

small nonmetal atoms

Explanation:

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What is the identity of the atom shown?
posledela

Answer:

A

Explanation:

Argon has 17 protons and 18 neutron

atomic number is the same as the protons number.

3 0
3 years ago
Read 2 more answers
Helen recorded the following data about the half-life of a radioisotope. Radioactive Decay of Radioisotope A Grams of Radioactiv
MissTica

Answer:

Line graph

Explanation:

I did it on Study Island

7 0
3 years ago
You need to prepare 1 L of the citric acid/citrate buffer. You have chosen to use Method 1 (see lab presentation). Calculate the
prisoha [69]

Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid]

<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

<em>Moles HX and NaX:</em>

Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

Moles HX = 0.300L * (0.45mol / L) = 0.135 moles HX - 0.065 moles NaOH = 0.070 moles HX

Replacing in H-H equation:

pH = 3.14 + log [0.065mol] / [0.070mol]

pH = 3.11 is the pH of the buffer

8 0
3 years ago
There are 9.88x1023 molecules of O2 available.
blondinia [14]

Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂

_______________

Part B needs an equation (usually a combustion of a hydrocarbon).

7 0
2 years ago
What would happen if the amount of chlorofluorocarbons would suddenly increase and what would happen to the climate?
mario62 [17]
If CFC increases, there will be a ozone depletion ! the UV rays starts entering and leads to mutation and deaths !

the temperature of the climate increases drastically !
4 0
3 years ago
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