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Akimi4 [234]
2 years ago
9

Air is classified as a mixture. What statement must be true about air? (4D)

Chemistry
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

C.)Air is made up of atoms of one elements

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The cycling of carbon between the living and non-living parts of the Earth system is an important result of which of the followi
lesantik [10]

Answer:

b. Plants and animals exchanging gases with the atmosphere

Explanation:

5 0
2 years ago
Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).
Zinaida [17]

Answer:

0.01185M = moles/0.02755L

0.02755*0.01185=0.00032647

Explanation:

7 0
3 years ago
Which chemical equation is unbalanced? c o2 right arrow. co2 sr o2 right arrow. 2sro 6h2 3o2 right arrow. 6h2o h2 h2 o2 right ar
netineya [11]

The unbalanced equation is one in which the moles of atoms are not equal on both sides of the reaction.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical equation is one in wgich the moles of atoms in the reactants side is equal to the moles of atoms on the product side.

The given equations of reaction is not clearly stated.

Therefore, the unbalanced equation is one in which the moles of atoms are not equal on both sides of the reaction.

Learn more about balanced equations at: brainly.com/question/11904811

#SPJ4

6 0
2 years ago
Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou
lesya [120]
First, let's compute the number of moles in the system assuming ideal gas behavior. 

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>
3 0
3 years ago
What are the common units for expressing solution concentration?
Ira Lisetskai [31]
It would be mol/dm^3 Formula of concentration: (no. of moles/volume of solution in dm^3) 1 cm^3 = 0.001dm^3 Hope this helped. :)
6 0
3 years ago
Read 2 more answers
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