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grigory [225]
3 years ago
12

What happens when water’s salinity increases?

Chemistry
2 answers:
bonufazy [111]3 years ago
8 0
When waters salinity increases it’s freezing point will decrease. This is one of the reasons why people salt the roads after a snow storm.
mamaluj [8]3 years ago
7 0

Answer:

Freezing point decreases.

Explanation:

Decreasing of freezing point is a colligative property, which depends on the number of solute particles in the solution. As the number of solute particle increases the freezing point decreases.  

Salt water has a lower freezing point than plain water.  

Salt water does not have a different mass than plain water. Option A is incorrect.

Salt water does not affect the buoyancy or the mineral dissolved in it.  Both option C and D are incorrect

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Number of sodium atom(s) in salt (NaCl)
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NaCl consists of one atom each of sodium and chlorine. Hence, each molecule of NaCl has 2 atoms total.

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Calculate the molarity of a solution obtained dissolving 10.0 g of cobalt(Ⅱ) bromide tetrahydrate in enough water to make 450 mL
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Answer:

<em><u>The molarity of the CoBr2•4H2O solution is  7.64 × 10-2 M</u></em>

Explanation:

Cobalt (II) bromide tetrahydrate

• Cobalt - A transition metal with Roman numeral (II) → charge: +2 → Co2+

• Bromide - anion from group 7A → -1 charge → symbol: Br-

• Tetrahydrate- tetra- means 4 and hydrate is H2O

The chemical formula of the compound is: CoBr2•4H2O

We then need to determine the number of moles of CoBr2•4H2O since this is the only information missing for us to find molarity. Notice that the volume of the solution is already given.

We’re given the mass of CoBr2•4H2O. We can use the molar mass of CoBr2•4H2O4 to find the moles.

•The molar mass of CoBr2•4H2O is:

CoBr2•4H2O  

1 Co x 58.93 g/mol Co = 58.93 g/mol

2 Br x 79.90 g/mol Br = 159.80 g/mol

8 H  x 1.008 g/mol H = 8.064 g/mol

4 O  x 16.00 g/mol O = 64.00 g/mol

________________________________________

                           Sum = <u>290.79 g/ mo</u>

The moles of CoBr2•4H2O is:

= 10.0 g CoBr2•4H2O x  \frac{ 1 mol  CoBr_2 . 4H_2O}{290.79 g CoBr_2 .  4H_2O}

= <u>0.0344  mol CoBr2•4H</u>

We know that the volume of the solution is 450 mL.

We can now calculate for molarity:

Convert mL to L → 1 mL = 10-3 L

Formula:

Molarity (M)= Mole of solute / Liters of solution

= 0.0344  mol CoBr2•4H  / 450 mL x 1 ml / 10^ -3 L

= 0.0764

=  7.64 × 10-2 mol/L

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