The chemical reaction is given as:
<span>C8H10+3O2 = C8H6O4+2H2O
We are given the initial amount of para-xylene for the reaction. We use this amount and the relation of substances from the reaction to obtain the amount of the acid produced.
204 g ( 1 mol / 106.18 g ) ( 1 mol C8H6O4 / 1 mol C8H10 ) ( 166.14 g / mol ) = 319.20 g terephthalic acid</span>
Balanced reaction for formation of water is ;
2H2 + O2 —> 2H2O
Stoichiometry of H2 to H20 is 2:2
1 mol of any gas occupies a volume of 22.4 L
Therefore it 22.4 L contains 1 mole
Then 1.24 L has -1/22.4 x 1.24 = 0.055 mol
Number of water moles formed = 0.055 mol
Therefore mass of water formed = 0.055 mol x 18 g/mol = 0.99 g of water is formed
