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3 years ago

Select all of the answers that apply.

Physics

2 answers:

ycow [4]3 years ago

8 0

You should go into your basement or if you don't have one just stay away from windows and unstable objects

mojhsa [17]3 years ago

6 0

Select all of the answers that apply.

If you're sitting at home and a hurricane or tornado warning is given, you should <u> </u> .

open all windows
stay away from all windows and unstable objects
go into the basement
go sit in your car
move to the top floor of your home

(the ones that are bolded are the correct answers...)

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if a diffraction grating produces a third-order bright spot for red light (of wavelength 650 nm ) at 68.0 ∘ from the central max

Mashutka [201]

Answer:

The angle is 25.34°.

Explanation:

Given that,

Wave length = 650 nm

Angle = 68.0°

We need to calculate the distance

For a diffraction grating

$d\sin\theta=m\lambda$

$d=\dfrac{2\times650\times10^{-9}}{\sin68.0}$

$d=2.10\times10^{-6}\ m$

We need to calculate the angle

Using formula for angle

$d\sin\theta=m\lambda$

$\sin\theta=\dfrac{m\times\lambda}{d}$

$\sin\theta=\dfrac{2\times450\times10^{-9}}{2.10\times10^{-6}}$

$\sin\theta=25.34^{\circ}$

Hence, The angle is 25.34°.

8 0

3 years ago

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s lat

victus00 [196]

Answer / Explanation

It is worthy to note that the question is incomplete. There is a part of the question that gave us the vale of V₀.

So for proper understanding, the two parts of the question will be highlighted.

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s later. You may ignore air resistance.

a) What must the height of the building be for both balls to reach the ground at the same time if (i) V₀ is 6.0 m/s and (ii) V₀ is 9.5 m/s?

b) If Vo is greater than some value Vmax, a value of h does not exist that allows both balls to hit the ground at the same time.

Solve for Vmax

Step Process

a) Where h = 1/2g [ (1/2g - V₀)² ] / [(g - V₀)²]

Where V₀ = 6m/s,

We have,

h = 4.9 [ ( 4.9 - 6)²] / [( 9.8 - 6)²]

= 0.411 m

Where V₀ = 9.5m/s

We have,

h = 4.9 [ ( 4.9 - 9.5)²] / [( 9.8 - 9.5)²]

= 1152 m

b) From the expression above, we got to realise that h is a function of V₀, therefore, the denominator can not be zero.

Consequentially, as V₀ approaches 9.8m/s, h approaches infinity.

Therefore Vₙ = V₀max = 9.8 m/s

4 0

3 years ago

Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot

frozen [14]

Answer:

0.285

Explanation:

Given two forces of different magnitude, it is important to note that the product of normal force and coefficient of kinetic friction should be equal to the sum of these two forces at equilibrium. Therefore, this can be Mathematically expressed as:

$N/\mu_k=F_1+F_2\\\\$

where N is normal force, $\mu$ is coefficient of static friction, F is force and subscripts 1 and 2 represent larger and smaller magnitude forces respectively. Making $\mu$ the subject of the formula then

$\mu_k=\frac{F_1+F_2}{N}$

Since normal force N is also given by mg where m is mass of object and g is acceleration due to gravity then substituting N with mg we obtain that

$\mu_k=\frac{F_1+F_2}{mg}$ and substituting the figures given in the question, taking g as 9.81 we obtain that

$\mu_k=\frac { 430 N+380 N}{290\times 9.81}=0.285$

Hence,the coefficient of kinetic energy is 0.285 as calculated

4 0

4 years ago

A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w

Grace [21]

Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque = distance from pivot * perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

4 0

3 years ago

The temperature of a superconductor is gradually lowered. At the critical temperature, how does the resistivity of the supercond

san4es73 [151]

At critical temperature, the resistivity of the superconductor

B. It suddenly drops to zero

Explanation:

Materials can be classified into three different types depending on their resistance:

Conductors: these materials have generally low resistance and allow electricity to pass through easily. The resistance of a conductor increases linearly with the temperature
Insulators: these materials do not allow electricity to pass through - so they have very high resistance
Semi-conductors: these are materials that are insulators are room temperature, however they becomes conductors when heated. Therefore, the resistance of a semiconductor decreases when the temperature increases
Superconductors: these are special materials that are normally conductors; however, at very low temperatures (we are talking about temperature very near to 0 K), their resistance becomes suddenly zero.

Therefore, the correct answer is:

B. It suddenly drops to zero

Learn more about current and resistance:

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#LearnwithBrainly

8 0

4 years ago